Your answer is 12.41x - 11.8
Compute the average number of units consumed: 504, 519, 576, 321, 256, 101, 76, 75, 127, 289, 367, and 511.
Komok [63]
The answer is about 310.17. Just have to add them all together and than divide by 12.
Answer:
square inches.
Step-by-step explanation:
<h3>Area of the Inscribed Hexagon</h3>
Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be
inches (same as the length of each side of the regular hexagon.)
Refer to the second attachment for one of these equilateral triangles.
Let segment
be a height on side
. Since this triangle is equilateral, the size of each internal angle will be
. The length of segment
.
The area (in square inches) of this equilateral triangle will be:
.
Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:
.
<h3>Area of of the circle that is not covered</h3>
Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is
inches, the radius of this circle will also be
inches.
The area (in square inches) of a circle of radius
inches is:
.
The area (in square inches) of the circle that the hexagon did not cover would be:
.
Answer: do the math, 39x
Step-by-step explanation:2+4=6 times 7=42-19=23+7=30+9=39x
Answer:
The lateral surface area of a prism is the sum of the surface areas of the sides of the prism.
Since the bases of the prism are triangles, there are three sides. The area of each lateral is the product of a side of the triangle times the height of the prism.
We can express this as Lateral Surface Area LSA = (s1xh) + (s2xh) + (s3+h), where "s1, s2, s3" are the lengths of the sides of the triangle and "h" is the height of the prism.
We can factor out "h" to get LSA = hx(s1+s2+s3) where the factor "s1+s2+s3" is the perimeter of the triangle.
Solving for "h", we get h = LSA / (s1+s2+s3)
For your specific problem, h = 300 / (4 + 5 + 6) = 300 / 15 = 20