Question

PLEASE HELP QUICK! I'M OFFERING 25PTS & BRAINLIEST ANSWER (Its only worth 10pts) I just need this done PLEASE SHOW YOUR WORK

Answer 1

QUESTION 1

The dimensions of the rectangular blanket are;

$l = (3x + 7)cm$

and

$w = (2x - 3)cm$

The perimeter is given by,

$p= 2w + 2l$

We substitute the dimensions to obtain,

$p = 2(2x - 3) + 2(3x + 7)$

Expand bracket to get,

$p = 4x - 6 + 6x + 14$

This simplifies to
$p =( 10x + 8 )cm$


QUESTION 2

When

$x = 4$
The perimeter becomes

$p =( 10(4) + 8 )cm$

$p =( 40 + 8 )cm$

$p =48cm$


QUESTION 3

Area is given by

$A=l \times w$
$A=(3x + 7)(2x - 3)$

We expand to get,

$A=6 {x}^{2} - 9x + 14x - 21$

This gives us,

$A=(6 {x}^{2} + 5x - 21) {cm}^{2}$

QUESTION 4

If
$x = 4$
Then the area becomes,

$A=6 {(4)}^{2} - 9(4)+ 14(4) - 21$

$A=6 \times 16 - 36+ 56- 21$

$A=96 - 36+ 56- 21$

$A=95 {cm}^{2}$

QUESTION 5.

When the length of the blanket is 5cm longer, then the length of the new blanket becomes

$l = (3x + 7 + 5)$

$l = (3x + 12)cm$

The width is still

$w = (2x - 3)cm$

The perimeter of the new blanket is

$p = 2(3x + 12) + 2(2x - 3)$

This implies that,

$p = 6x + 24+ 4x - 6$

$p = 10x +18$

Comparing to the old perimeter which is

$p = 10x +8$,

The perimeter changes by 10 units