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Murrr4er [49]
3 years ago
5

PLEASE HELP QUICK! I'M OFFERING 25PTS & BRAINLIEST ANSWER (Its only worth 10pts) I just need this done PLEASE SHOW YOUR WORK

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0
QUESTION 1

The dimensions of the rectangular blanket are;

l = (3x + 7)cm

and

w = (2x - 3)cm

The perimeter is given by,

p= 2w + 2l

We substitute the dimensions to obtain,

p = 2(2x - 3) + 2(3x + 7)

Expand bracket to get,

p = 4x - 6 + 6x + 14

This simplifies to
p =( 10x + 8 )cm


QUESTION 2

When

x = 4
The perimeter becomes

p =( 10(4) + 8 )cm

p =( 40 + 8 )cm

p =48cm


QUESTION 3

Area is given by

A=l \times w
A=(3x + 7)(2x - 3)

We expand to get,

A=6 {x}^{2} - 9x + 14x - 21

This gives us,

A=(6 {x}^{2} + 5x - 21) {cm}^{2}

QUESTION 4

If
x = 4
Then the area becomes,

A=6 {(4)}^{2} - 9(4)+ 14(4) - 21

A=6 \times 16 - 36+ 56- 21

A=96 - 36+ 56- 21

A=95 {cm}^{2}

QUESTION 5.

When the length of the blanket is 5cm longer, then the length of the new blanket becomes

l = (3x + 7 + 5)

l = (3x + 12)cm

The width is still

w = (2x - 3)cm

The perimeter of the new blanket is

p = 2(3x + 12) + 2(2x - 3)

This implies that,

p = 6x + 24+ 4x - 6

p = 10x +18

Comparing to the old perimeter which is

p = 10x +8,

The perimeter changes by 10 units
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