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boyakko [2]
3 years ago
10

A text font fits 12 characters per inch. Using the same font, how many characters can be expected per yard of text?

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0
I<span>f an inch would fit 12 characters and 1 yard has 36 inches. then, a yard would fit 432 characters.

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Hi help me please i need help
larisa86 [58]

Answer:

First answer is correct.

Step-by-step explanation:

5 0
3 years ago
What is 2 less than five times a number
miv72 [106K]

Answer:

2<5*X

Step-by-step explanation:

Hope this helped, Have a Wonderful Day!!

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3 years ago
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An isotope decays at a rate of -0.0049% per year. Find the half life. (show the work)
cricket20 [7]

Answer:

  14,146 years

Step-by-step explanation:

The annual multiplier is (1 -0.0049%) = 0.999951. We want to find the number of times this needs to be multiplied to make the product 1/2.

  0.5 = 0.999951^t

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7 0
3 years ago
Construct the confidence interval for the population mean mu. c = 0.90​, x = 16.9​, s = 9.0​, and n = 45. A 90​% confidence inte
Georgia [21]

Answer:

The  90%  confidence interval for population mean is   14.7  <  \mu  <  19.1

Step-by-step explanation:

From the question we are told that

   The sample mean is  \= x  =  16.9

    The confidence level is  C  =  0.90

     The sample size is  n  =  45

     The standard deviation

Now given that the confidence level is  0.90 the  level of significance is mathematically evaluated as

       \alpha =  1-0.90

       \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2}  from the standardized normal distribution table. The values is  Z_{\frac{\alpha }{2} } =  1.645

The  reason we are obtaining critical values for \frac{\alpha }{2}  instead of  that of  \alpha  is because \alpha  represents the area under the normal curve where the confidence level 1 - \alpha (90%)  did not cover which include both the left and right tail while \frac{\alpha }{2}  is just considering the area of one tail which is what we required calculate the margin of error

  Generally the margin of error is mathematically evaluated as

        MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

         MOE  = 1.645*  \frac{ 9 }{\sqrt{45} }

         MOE  = 2.207

The  90%  confidence level interval is mathematically represented as

      \= x  -  MOE  <  \mu  <  \= x  +  MOE

substituting values

     16.9 -  2.207  <  \mu  <  16.9 +  2.207

    16.9 -  2.207  <  \mu  <  16.9 +  2.207

     14.7  <  \mu  <  19.1

         

3 0
3 years ago
In mathematics what is 1 plus 1
Sergio039 [100]
I believe the answer is 2
4 0
3 years ago
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