Answer : The correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit
Explanation :
Conversion of degree Celsius to Kelvin :
Conversion of degree Celsius to degrees Fahrenheit :
By using these two conversion factors, we get the three temperature readings all mean the same thing.
For option A :
For option B :
For option C :
For option D :
From the given options, only option (D) is correct.
Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit
Answer:
distance travelled by the block is 0.796 m
{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }
Explanation:
Given that;
mass of block m = 0.200 kg
distance travelled d = 0.796 m
time t = 2.00 s
m₂ = 0.400 kg
If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?
Now, using the second equation of motion;
d = ut + ( × at²)
as the object started from rest, u=0
so, we substitute
0.796 = 0×2 + ( × a(2)²)
0.796 = 0 + ( × 4a)
0.796 = 2a
a = 0.796 / 2
a = 0.398 m/s²
using first equation of motion
= u + at
we substitute
= 0 + 0.398 × 2
= 0.796 m/s
now, average velocity is given as;
= ( 0.796 m/s + 0 ) / 2
= ( 0.796 m/s + 0 ) / 2
now, distance as the block moves in 2s will be;
D = [( 0.796 m/s + 0 ) / 2 ] × 2
D = 0.796 m
Therefore, distance travelled by the block is 0.796 m
{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }