Question

An automobile engine has an efficiency of 19.0%. If it produces 23.0 kJ of mechanical work per second, the heat rejected per second from the engine is closest to: (a) 77.0 kJ (b) 81.5 kJ (c)86.5 kJ (d) 92.0 kJ (e) 98.1 kJ

Answer 1

Answer:

(e) 98,1 KJ

Explanation:

The engine produces 19%; it means, it rejects 81% of energy. ⇒ 81/19=4.26 times.

The engine produces 23 kJ; it means it rejects 23 * 4.26 = 98.05263 kJ