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Anna [14]
3 years ago
9

A sample has a pH of -0.248 (yes, it really is possible to have a negative pH). Find

Chemistry
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

pOH= 14.248

[H+]=1.77 M

[OH-]=5.65 x10^-15M

Explanation:

pH+pOH= 14

pOH= 14-pH

pOH=14-(-0.248)

pOH= 14.248

[H+]=10^-pH= 10^-(-0.248)=1.77 M

[OH-]=10^-pOH= 10^-14.248=5.65 x10^-15M

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What was removed from the glucose molecules when they bonded to form maltose
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Two hydrogen atoms and one oxygen atom (water) was removed.

Explanation:

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3 years ago
What is the percent composition by mass of each element in Co(HSO4)2?
MrRissso [65]

Answer:

54.1 % Ca, 43.2 % O, 2.7% H

Explanation:

Molecular formula for calcium hydroxide is Ca(OH)₂

As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.

1 mol of hydroxide weighs 74.08 g

1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca

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2 moles of H therefore 2 g are H

Percentage composition is known as (Mass of element/Total mass) . 100

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2 years ago
The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma
Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C=p_o= 187.54 mmHg

Vapor pressure of the solution at 65 °C= p_s

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water=n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol

Moles of ethylene glycol=n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}

p_s=173.83 mmHg

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

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3 years ago
I need help with science pls help me
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Answer:

Explanation:

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