Answer:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
The function of HCl is oxidize the gold.
Explanation:
It is possible to balance the reaction seeing each compound as a variable and take an equation for each atom, thus:
Au(s) + HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)
a + b + c = d + e + f
Au: a = d <em>(1)</em>
H: b + c = d + 2f <em>(2)</em>
N: b = e <em>(3)</em>
O: 3b = 2e + f <em>(4)</em>
Cl = c = 4d <em>(5)</em>
Assuming <em><u>a = 1</u></em>:
<em><u>1 = d</u></em> <em>(1)</em>
<u><em>c = 4</em></u> <em>(5)</em>
b + 3 = 2f <em>(2)</em>
3b = 2e + f <em>(4)</em>
As b = e:
b = f <em>(4)</em>
<em><u>f = 3</u></em>; <em><u>b = 3</u></em>; <em><u>e = 3</u></em>
Thus, balanced reaction is:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
<em>The function of HCl is oxidize the gold</em> that before reaction is Au⁰ and afte ris Au⁺³
I hope it helps!
Elements from 57 to 71 are Lanthanoids and from 89 to 103 are Actinoids. Simply I would say Actinoids have less similarity in chemical properties than Lanthanoids. On the other hands, Actinoids have randomized chemical strutural bonds.
Answer:
C. Tetrahedral
Explanation:
Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which means it has tetra (which translates to four) domains hence tetrahedral.
