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2 years ago

Complete the following chart to fill in the blanks

Chemistry

1 answer:

raketka [301]2 years ago

7 0

Im so sorry i don’t know I just need to answer 2 questions for me to be Able to ask

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Can anyone please help me with my chemistry homework? It’s about molarity. I can’t message anyone here because I’m new to brainl

GREYUIT [131]

Answer:

ok sure

Explanation:

4 0

2 years ago

The reaction of iron with oxygen to form iron oxide is an example of an oxidation–reduction reaction: 4fe + 3o2 → 2fe2o3. in thi

nadya68 [22]

Answer:-

Oxygen gains electrons and is reduced.

Explanation:-

For this reaction the balanced chemical equation is

4Fe + 3O2 --> 2Fe2O3

When Oxygen is present as oxygen gas, the oxidation number of O is Zero since it is the only element present in Oxygen gas.

Similarly Iron is present in Fe with oxidation number Zero.

In the case of Fe2O3, Oxygen has the oxidation number -2 while Iron has +3.

So the oxidation number of Oxygen goes from Zero to -2.

Since the oxidation number decreases Oxygen is reduced.

Since reduction involves gain of electrons, Oxygen gains electrons.

4 0

3 years ago

Does anyone know the answers for these

Alexeev081 [22]

Answer: 1. 0.045moles

2. 2.10 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

1. $\text{Number of moles of zinc nitrate}=\frac{8.51g}{189.36g/mol}=0.045moles$

2. Mass of $C_2H_4=moles\times {\text {Molar mass}}=0.075moles\times 28.05g/mol=2.10g$

4 0

2 years ago

Please help me out Fast people

kifflom [539]

I think convergent but could be wrong

4 0

3 years ago

Read 2 more answers

Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen

alexgriva [62]

Answer:

$V_{base}=24.04mL$

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

$2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O$

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

$2M_{base}V_{base}=M_{acid}V_{acid}$

Therefore, for is to compute the volume of the used base, we proceed as shown below:

$V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}$

And we plug in to obtain:

$V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL$

Best regards!

8 0

3 years ago