In the given table we note that there are six clear subintervals: [0, 0.5], [0.5, 1.0], [1.0, 1.5], [1.5, 2.0], [2.0, 2.5], and
gizmo_the_mogwai [7]
Answer:
The width is 0.5.
Δt, can be stated as follows = 0.5
Step-by-step explanation:
The change is 0.5
Answer:
680 games
Step-by-step explanation:
Suppose that 681 tennis players want to play an elimination tournament.
1st round:
One of 681 players, chosen at random, sits out that round and 680 players play. There will be 340 winners plus one player which sits - 341 players for the next round and 340 games
2nd round:
There will be 170 winners plus one player which sits - 171 players for the next round and 170 games
3rd round:
There will be 85 winners plus one player which sits - 86 players for the next round and 85 games
4th round:
There will be 43 winners - 43 players for the next round and 43 games
5th round:
There will be 21 winners plus one player which sits - 22 players for the next round and 21 games
6th round:
There will be 11 winners - 11 players for the next round and 11 games
7th round:
There will be 5 winners plus one player which sits - 6 players for the next round and 5 games
8th round:
There will be 3 winners - 3 players for the next round and 3 games
9th round:
There will be 1 winner plus one player which sits - 2 players for the next round and 1 game
10th round - final:
1 champion and 1 game.
In total,
340 + 170 + 85 + 43 + 21 + 11 + 5 + 3 + 1 + 1 = 680 games
Answer:
Number of flowers required = 1256
Step-by-step explanation:
Circumference of a circle is given by the formula,
Circumference = 2πr
Here, r = radius of the circle
For a circle with radius = 100 in.
Therefore, circumference = 2π(100)
= 200π
= 628.32 ft
Distance between each flower = 6 in
≈ 
= 0.5 ft
Number of flowers = 
= 
= 1256.63
≈ 1256
Therefore, number of flowers required = 1256
1) Given: ds / dt = 3t^2 / 2s
2) Separate variables: 2s ds = 3t^2 dt
3) Integrate both sides:
∫ 2s ds = ∫ 3t^2 dt
s^2 + constant = t^3 + constant
=> s^2 = t^3 + constant
=> s = √ (t^3 + constant)
Answer: option B.
