167 i believe according to my calculations
Q(t) = 40((e^-t) - (e^-2t))
For q(t) to be maximum dq/dt = 0
dq/dt = 40(-(e^-t) + 2(e^-2t) = 0
2e^-2t - e^-t = 0
2e^-2t = e^-t
e^t = 2
t = ln 2
q(ln 2) = 40((e^(-ln 2) - (e^(-2ln 2)) = 40(1/2 - 1/4) = 40(1/4) = 10
Therefore, thw maximum amount of drug in the bloodstream at one time is 10 mg.
Answer:
it should b. Hope this helps!
Answer: The width of the field = 160 feet
Step-by-step explanation:
We are given that , A field is
yards wide.
That means , The width of the field =
yards
Since , the fraction is in mixed for , so first we convert this into improper fraction.

Therefore , the width of the field =
yards
Since 1 yard = 3 feet.
⇒ the width of the field =
feet
Therefore , the width of the field = 160 feet
The answer would be b
hope that helps