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3 years ago

Modeling a Bicycle Wheel Complete the table

Mathematics

2 answers:

Sladkaya [172]3 years ago

7 0

Answer:

a= 6

b= 7

c= 8

d= 7

e= 6

dem82 [27]3 years ago

5 0

Answer:6,7,8,7,6

Step-by-step explanation:

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which ordered pairs in the form (x, y) are solutions to the equation 3x−4y=21 ? Select each correct answer. (−1, −6) (−3, 3) (11

Valentin [98]

Answer:

see explanation

Step-by-step explanation:

To determine which ordered pairs are solutions to the equation

Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.

(- 1, - 6)

3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution

(- 3, 3)

3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution

(11, 3)

3(11) - 4(3) = 33 - 12 = 21 = right side ← thus a solution

(7, 0)

3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution

The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation

3 0

3 years ago

Read 2 more answers

Find b. Question 19 options: 70.1 57.7 31.5 43.8

Reptile [31]

Answer: 57.7

Step-by-step explanation:

6 0

3 years ago

Factor the expression 10x+15y=

gayaneshka [121]

5(2x+3y) is the most it can be factored. You first have to find the greatest common factor and once thats done just try using methods such as the diamond. The only thing it was able to do using the methods was this.

8 0

3 years ago

2x-7=-3x+18 solve for x

Gre4nikov [31]

Answer:

x=5

Step-by-step explanation:

2x−7=−3x+18

Step 1: Add 3x to both sides.

2x−7+3x=−3x+18+3x

5x−7=18

Step 2: Add 7 to both sides.

5x−7+7=18+7

5x=25

Step 3: Divide both sides by 5.

x=5

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%20%5Crm%5Csum_%7Bn%20%3D%201%7D%5E%20%5Cinfty%20%28%20-%201%20%7B%29%7D%5E%7Bn%20-%201%7D%

victus00 [196]

Let

$\displaystyle f(x) = \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)! (2n+1)}$

The exponent is indeed $2n-1$ - not a typo!

Take the antiderivative of $f$ , denoted by $F$ . This recovers a factor of $2n$ in the denominator, which lets us condense it to a single factorial.

$\displaystyle F(x) = \int f(x) \, dx = C + \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n}}{(2n+1)!}$

Recall the series expansion of sine,

$\displaystyle \sin(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}$

Then with a little algebraic manipulation, we get

$\displaystyle F(x) = \int f(x) \, dx = C + 1 - \frac{\sin(x)}x$

Differentiate to recover $f$ .

$f(x) = \dfrac{\sin(x) - x\cos(x)}{x^2}$

Finally, $f(\pi) = \frac1\pi$ , so our sum is

$\displaystyle \pi^2 f(\pi) = \sum_{n=1}^\infty (-1)^{n-1} \frac{\pi^{2n+1}}{(2n-1)! (2n+1)} = \boxed{\pi}$

3 0

1 year ago