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ruslelena [56]
4 years ago
9

What type of bond will always conduct electricity?

Chemistry
1 answer:
BaLLatris [955]4 years ago
7 0
The metallic bond will always conduct electricity
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Write a balanced half-reaction for the oxidation of gaseous nitric oxide NO to nitrate ion NO−3 in acidic aqueous solution. Be s
crimeas [40]

Answer:

2H_2O(l)+NO(g)\rightarrow NO_3^-(aq) +4H^+(aq)+3e^-

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the initial version of the half-reaction as follows:

NO\rightarrow NO_3^-

Now, we assign the oxidation numbers to both nitrogen atoms:

N^{2+}O\rightarrow N^{5+}O_3^-

It means three electrons are carried, two water molecules are needed on the left side in order to balance the oxygen atoms and consequently four hydronium ions to balance hydrogen atoms in acidic media:

2H_2O(l)+NO(g)\rightarrow NO_3^-(aq) +4H^+(aq)+3e^-

Regards!

3 0
3 years ago
Plants and animals need to protect themselves to survive. Select the statement that best describes the adaptions of animals and
saul85 [17]
I need points lol sorry for wasting ur time we
3 0
3 years ago
The first excited state of Ca is reached by absorption of 422.7 nm light. Find the energy difference (kJ/mole) between the groun
dedylja [7]

For the excited state of Ca at the absorption of 422.7 nm light,the energy difference  is mathematically given as

E= 4.70x10-22 kJ/mol

<h3>What is the energy difference (kJ/mole) between the ground and the first excited state?</h3>

Generally, the equation for the Energy  is mathematically given as

E = nhc / λ

Where

h= plank's constant

h= 6.625x 10-34 Js

c = speed of light

c= 3x 108 m/s

Therefore

E = 1*(6.625x 10-34 Js)( 3x 10^8 m/s) / ( 422.7x10^-9)

E= 4.70x10-22 kJ/mol

In conclusion, Energy  

E= 4.70x10-22 kJ/mol

Read more about Energy

brainly.com/question/13439286

5 0
2 years ago
How to calculate the pH of NH4OH(0.1M)
anastassius [24]
Answer is: pH of ammonium hydroxide is 11.13.
Chemical reaction of ammonium hydroxide in water: NH₄OH → NH₄⁺ + OH⁻<span>.
</span>

Kb(NH₄OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₄OH<span>) = 0.1 M.
c(NH</span>₄⁺) = c(OH⁻<span>) = x.
c(</span>NH₄OH<span>) = 0.1 M- x.
Kb = c(NH</span>₄⁺) · c(OH⁻) / c(NH₄OH<span>).
0,000018 = x² /  0.1 mol/L - x</span>.

Solve quadratic equation: x = c(OH⁻) = 0.00133 M.

pOH = -logc(OH⁻).

pOH = 2.87.

pH = 14 - 2.87.

pH = 11.13.


8 0
3 years ago
SOMEONE PLEASE HELP ME ITS SCIENCE
andreev551 [17]

Answer:

2

Explanation:

The total number of atoms in silver sulfate Ag2SO4 is 2

6 0
3 years ago
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