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rodikova [14]
3 years ago
14

Do all colors of light travel at the same speed

Chemistry
2 answers:
bogdanovich [222]3 years ago
5 0

Answer:

No because some lights we cannot see because they move to slow or they move to fast for our eye to see. There is just a small little gap compared to what light rays we can actually see. In this picture you can see what I mean.

Explanation:

Furkat [3]3 years ago
5 0
No they don’t cause they don’t
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For the IMAGINARY molecular compound fluorine tri nitride having the formula: FN3
arsen [322]

Answer:

Hyu

Explanation:

5 0
2 years ago
The density of water is 1 gm/ml. An object has a mass of 58 grams. What volume must it have in order to float in water?
Keith_Richards [23]

Answer:

58mL

Explanation:

Given parameters:

Density of water  = 1g/mL

Mass of object  = 58g

Unknown:

The volume the object must have to be able to float in water = ?

Solution:

To solve this problem, we know that the object must have density value equal to that of water or less than that of water to be able to float.

We then set its density to that of water;  

   Density  = \frac{mass}{volume}  

      Volume  = \frac{mass}{density}  

So;

      Volume  = \frac{58}{1}   = 58mL

7 0
2 years ago
0.17 M KCHO2 Find the pH
SashulF [63]
I believe the pH is 7. If you would like me to explain comment.
6 0
3 years ago
If 45.0 mL of ethanol (density=0.789 g/mL) initially at 9.0 C is mixed with 45.0 mL of water (density=1.0 g/mL) initially at 28.
Klio2033 [76]

Answer : The final temperature of the mixture is 22.7^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

(\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ethanol = 2.3J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ethanol

m_2 = mass of water

\rho_1 = density of ethanol = 0.789 g/mL

\rho_2 = density of water = 1.0 g/mL

V_1 = volume of ethanol = 45.0 mL

V_2 = volume of water = 45.0 mL

T_f = final temperature of mixture = ?

T_1 = initial temperature of ethanol = 9.0^oC

T_2 = initial temperature of water = 28.6^oC

Now put all the given values in the above formula, we get

(0.789g/mL\times 45.0mL)\times (2.3J/g^oC)\times (T_f-9.0)^oC=-(1.0g/mL\times 45.0mL)\times 4.18J/g^oC\times (T_f-28.6)^oC

T_f=22.7^oC

Therefore, the final temperature of the mixture is 22.7^oC

4 0
3 years ago
A compound of mercury and oxygen is heated in order to decompose the compound. A 4.08 grams sample of mercury oxide upon heating
arlik [135]

Answer:

HgO (empirical formula)

Explanation:

4.08 - 3.78 = 0.3g (oxygen)

(\frac{4.08}{201})   \:  \:  \:  (\frac{0.3}{16} )

0.02 : 0.02

0.02/0.02 : 0.02/0.02

1 : 1 (ratio)

HgO ( empirical formula)

2HgO ----> 2Hg + O2 ( your equation correct)

7 0
2 years ago
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