1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vsevolod [243]
3 years ago
13

Someone help meh with this and tell me how u got this!

Mathematics
2 answers:
Galina-37 [17]3 years ago
4 0
Blah Lala blahdjejejjeje
jolli1 [7]3 years ago
3 0
The answer is 12.57. because it is the hundredth place and 10 x 0.05 is 0.5
You might be interested in
Find the complete factored form of the polynomial 48m^5+8n^2
scZoUnD [109]

Answer:

8 ( 6 m 5^ + n 2^ )

3 0
3 years ago
Read 2 more answers
choose the most appropriate answer. temperature(10 seconds), temperature(10), and t(10) all represent which of the following? a.
Mice21 [21]
B. the temperature of a liquid after it is heated for 10 seconds
7 0
3 years ago
Triangles O N M and S R Q are shown. Angles O N M and S R Q are congruent. The length of side N M is 10 and the length of side S
valina [46]

Answer:

Option C.

Step-by-step explanation:

In △ONM and △SRQ,

\angle ONM\cong \angle SRQ

NM=10

SR=20

NO=8

QR=x

We need to find the value of x that will make △ONM similar to △SRQ by the SAS similarity theorem.

According to SAS similarity theorem, two triangle are similar if two corresponding sides in both triangles are proportional and the included angle in both are congruent.

It is given that \angle ONM\cong \angle SRQ. So, both triangles are similar by SAS if

\dfrac{NO}{NM}=\dfrac{SR}{QR}

Substitute the given values.

\dfrac{8}{10}=\dfrac{20}{x}

8\times x=20\times 10

8x=200

Divide both sides by 8.

x=\dfrac{200}{8}

x=25

Therefore, the correct option is C.

7 0
3 years ago
Read 2 more answers
Can anyone help me please
7nadin3 [17]

Answer:

noqijauaajajajajabbaababbaa

7 0
2 years ago
A customer desires to mix her own concrete. The clerk knows that the ratio of cement to sand to gravel is 1:3:4. If the customer
Aleks [24]

Answer:

The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Step-by-step explanation:

Given as :

The ratio of cement to sand to gravel = 1 : 3 : 4

The total quantity of dry mix required = 1000 pounds

Let The quantity of cement required = 1 × x pounds

The quantity of sand required = 3 × x pounds

The quantity of gravel required = 4 × x pounds

So, According to question

The total quantity of dry mix required = The quantity of cement required + The quantity of sand required + The quantity of gravel required

Or, x + 3 x + 4 x = 1000 pounds

Or, 8 x = 1000 pounds

∴  x = \frac{1000}{8}

I.e x = 125

So , The quantity of cement required = 1 × 125 pounds = 125 pounds

The quantity of sand required = 3 × 125 pounds = 375 pounds

The quantity of gravel required = 4 × 125 pounds = 500 pounds

Hence The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Answer

8 0
3 years ago
Other questions:
  • the sales tax in Illinois is 6.25%. About how much will a pair of jeans that has a ticket price of $48.99 cost, including sales
    15·1 answer
  • 60 cars to 24 cars what is the percent of change can you tell me answer and explain thanks
    12·1 answer
  • Is 8/10 greater than 3/4
    11·2 answers
  • Dion puts seven tenths of his allowance into savings each month what fraction of his saving doesnt go in
    12·1 answer
  • Chip begins his ride slowly but then stops to talk with some friends. After a few minutes, he continues his ride, gradually incr
    6·1 answer
  • PLZZZ HELP!
    9·1 answer
  • Which quadrilateral and why?
    6·1 answer
  • Evaluate (A n C) - B
    8·1 answer
  • Help please max points
    8·2 answers
  • One afternoon, Dillon and 3 friends visit the zoo. They split the cost of parking the car evenly. Then each person buys a ticket
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!