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Vsevolod [243]
3 years ago
13

Someone help meh with this and tell me how u got this!

Mathematics
2 answers:
Galina-37 [17]3 years ago
4 0
Blah Lala blahdjejejjeje
jolli1 [7]3 years ago
3 0
The answer is 12.57. because it is the hundredth place and 10 x 0.05 is 0.5
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Cody increased the amount of money he saves each week from $40 to $75. By what percentage did Cody increase the amount of money
Bas_tet [7]

how did that stup di boy friend beat me in week 6Step-by-step explanation:

7 0
3 years ago
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FOR 15 POINTS I WILL GIVE BRAINLEST IF YOU ARE CORRECT! What is the solution to the system that is created by the equation y = 2
goblinko [34]

The solution point is (4,2).

Step-by-step explanation:

Equation of straight line passing through the points (0,0) and (4,2) is given by

⇒ 2y = x ............ (1)

And the other straight line is y = - x + 6 .............. (2)

Now, solving equations (1) and (2) we get, y = - 2y + 6

⇒ 3y = 6

⇒ y = 2

And from equation (1) we get, x = 2y = 4

Therefore, the solution point is (4,2). (Answer)

6 0
3 years ago
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i need help in finding the sum for (16 − x2) + (−14x2 + 7x5 − 17x4 + 9) plz help :( im rlly bad at math
Evgesh-ka [11]

Answer:

-50

Step-by-step explanation:

7 0
3 years ago
Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
3 years ago
Solve for x: x5 + x4 − 7x3 − 7x2 − 144x − 144 = 0
motikmotik

x^5 + x^4 - 7x^3 - 7x^2 -144x - 144 = 0 \\x^4(x+1)-7x^2(x+1)-144(x+1)=0\\(x^4-7x^2-144)(x+1)=0\\\\x+1=0\Rightarrow x=-1\\\\x^4-7x^2-144=0\\x^4-16x^2+9x^2-144=0\\x^2(x^2-16)+9(x^2-16)=0\\(x^2+9)(x^2-16)=0\\(x^2+9)(x-4)(x+4)=0\\\\x^2+9=0\vee x-4=0 \vee x+4=0\\x=4 \vee x=-4\\\\x\in\{-4,-1,4\}

6 0
3 years ago
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