what mass contains 6.0x10^23 atoms? a) 6.0g of carbon b)16g of sulfur c)3.0g of helium d)28g of silicon

Which gas law would you use for the following problem: What pressure is required to hold 8.0 moles of oxygen gas in an 8.0 L con

emmainna [20.7K]

Answer:

Ideal Gas Law ( PV = nRT)

Explanation:

Using the Ideal Gas Law, we have; PV = nRT

Where P= Pressure = ?

V= Volume = 8.0 L

n = moles = 8.0

R = Gas constant = 0.0821 L.atm/mol/K

T = 80° c + 273 = 353.15K

Therefore Pressure would be; P = nRT/ V = 8 x 0.0821 x 353.15 / 8 = 28.9atm

5 0

3 years ago

What can be produced by splitting unraniam 235

Ainat [17]

It splits into two equal nuclei of approx. equal mass.

7 0

3 years ago

5. What percentage of energy generation is

Maslowich

Answer:

i think it's B maybe..I'm not sure

5 0

3 years ago

The half reaction of an oxidation reduction reaction shows that iron gains electrons. what does this electron gain mean for iron

chubhunter [2.5K]

Answer: The correct option is C.

Explanation:

Oxidation reactions are a type of chemical reactions in which a substance looses electrons and forms positive charge. The substance undergoing this reaction is being oxidized.

$A\rightarrow A^++e^-$

Reduction reactions are a type of chemical reactions in which a substance gains electrons and forms negative charge. The substance undergoing this reaction is being reduced.

$A^++e^-\rightarrow A$

For the half reaction in which iron gains electrons means that iron is getting reduced.

Hence, the correct option is C.

6 0

3 years ago

Read 2 more answers

Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

6 0

3 years ago