What separation technique can the mixture of sodium chloride and iodine be separated
1 answer:
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Answer:
3.96 × 10⁻³ mol Pb
Explanation:
Step 1: Find molar mass
Pb (Lead) - 207.2 g/mol
Step 2: Use Dimensional Analysis
= 0.003962 mol Pb
Step 3: Simplify
We have 3 sig figs
0.003962 mol Pb ≈ 0.00396 mol Pb
0.00396 mol Pb = 3.96 × 10⁻³ mol Pb