Question

Write the ions present in solution of pb(no3)2. express your answers as chemical formulas separated by a comma. identify all of the phases in your answers.

Answer 1

The ions present in the solution of ${\text{Pb}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}} \right)_{\text{2}}}$ are $\boxed{{\text{P}}{{\text{b}}^{2 + }},\;{\text{NO}}_3^-}$ and both these ions are present in the aqueous phase.

Further explanation:

Chemical formula:

It provides complete information about the elements and their respective proportions in any particular compound.

Following are the steps to write the chemical formula of a compound:

1. The letter symbols of cations and anions are to be written.

2. Charges on cation and anion are to be identified. Generally, group 1 elements have +1 charge, group 2 elements have -2 charge, Group 16 elements have -2 charge, group 17 elements have -1 charge.

3. The total positive and negative charge needs to be balanced out. This is done by writing the charge on anion as a subscript for cation and the charge on cation as a subscript for anion.

${\text{Pb}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}} \right)_{\text{2}}}$ is formed from one ${\text{P}}{{\text{b}}^{2+}}$ and two ${\text{NO}}_3^-$ ions. (Refer to the structure in the attached image). So when it is present in the solution, its constituent ions are produced and therefore ${\text{P}}{{\text{b}}^{2+}}$ and ${\text{NO}}_3^-$ are the ions present in the solution of ${\text{Pb}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}} \right)_{\text{2}}}$. Both these ions are present in the aqueous phase.

Learn more:

1. Component of John Dalton’s atomic theory: brainly.com/question/2357175

2. Basis of investigation for the scientists: brainly.com/question/158048

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Some basic concepts of chemistry

Keywords: chemical formula, Pb2+, NO3-, one, two, letter symbols, elements, cation, anion, proportion, compound, aqueous phase.

Answer 2

The decomposition of the given compound, Pb(NO3)2, will yield 3 different simpler compounds which are lead oxide (PbO), nitrogen dioxide (NO2), and oxygen (O2). Based on the given chemical formula, the ionic component of the compound are Pb²⁺ and 2 ions of NO₃²⁻.

The phases of these compounds will have to be solid and aqueous.