The reaction between zinc and silver nitrate is
Moles of Zn = m /M = 599 /65 = 9.2 mol
Moles of AgNO3 = m /M = 1500 /169 = 8.87 mol
Silver nitrate is reacting completely to give silver
Thus, moles of Silver nitrate is equivalent to silver = 8.87
For mass of silver produced
m /M = 8.87 = m /107
m = 949.24 g
Hence, the given quantity of reactants are sufficient to produce 800 g of silver as the amount of silver produced is 949.24 g
Answer: The ground-state electronic configuration of
1)
2)
Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.
Atomic number of the element = Number of electrons.
Atomic number = 44
Number of electrons = 44
Electronic configuration of Ru-element =
To form , 2 electrons are released from the neutral Ru-element.
So, the electronic configuration of
Atomic number = 74
Number of electrons = 74
Electronic configuration of W-element =
To form , 3 electrons are released from the neutral W-element.
So, the electronic configuration of