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2 years ago

15

Answer this pls I need this help

2 answers:

krok68 [10]2 years ago

8 0

a) 10 * 10 * 10 (volume of rectangular prism is <em>b * w * h, which are all 10 in</em>)

b) 10³ (10 * 10 * 10 is <em>10 multiplied itself 3 times</em>)

c) 6 * 6 (each layer has <em>6 rows</em>, and each row has <em>6 columns</em>)

d) 6 * 6 * 6 (<em>6 rows, 6 columns, 6 layers</em>)

e) 6³ (6 * 6 * 6 is <em>6 multiplied itself 3 times</em>)

f) Complete the multiplication: 6 * 6 = 36 --> 36 * 6 = 216 balls

Paha777 [63]2 years ago

4 0

Do you need help with all of it?

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Identify the maximum and minimum values of the function y = 3 cos x in the interval [–2π, 2π]. Use your understanding of transfo

8_murik_8 [283]

You would need to do this with a graphing calculator

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2 years ago

What is the completely factored form of 8 x square minus 50

goblinko [34]

Lets factor first to see if we can make the problem simple
2(4x^2-25)
now we see that in parenthesis we have 2 square numbers
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25=(5)^2
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2(2x+5)(2x-5)

8 0

2 years ago

A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

So

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

3 0

2 years ago

Determine any data values that are missing from the table, assuming that the data represent a linear function.

Varvara68 [4.7K]

Answer:

c. 14

Step-by-step explanation:

Let the missing y value be y2.

If the data represent a linear function, then:

$\frac{6 - 2}{2 - 1} = \frac{y_2 - 6}{4 - 2}$

$\frac{4}{1} = \frac{y_2 - 6}{2}$

$4 = \frac{y_2 - 6}{2}$

Multiply both sides by 2

$4 \times 2 = \frac{y_2 - 6}{2} \times 2$

$8 = y_2 - 6$

Add 6 to both sides

$8 + 6 = y_2 - 6 + 6$

$14 = y_2$

The missing value is 14

6 0

2 years ago

Which decimal is equivalent to 13/11

TiliK225 [7]

Answer:

1.18 is the answer but if u want to round u have the answer as 1.20=1.2

7 0

3 years ago

Read 2 more answers