The solution is:tan(θ) = opp / adj tan(θ) = y/x xtan(θ) = y
Find x:
x = y/tan(θ)
So x = 3/tan(π/6)
Perform implicit differentiation to get the equation:
dx/dt * tan(θ) + x * sec²(θ) * dθ/dt = dy/dt
Since altitude remains the same, dy/dt = 0. Now...
dx/dt * tan(π/6) + 3/tan(π/6) * sec²(π/4) * -π/4 = 0
changing the equation, will give us:
dx/dt = [3/tan(π/6) * sec²(π/6) * π/4} / tan(π/6) ≈ 12.83 km/min
Density can be found when mass and volume is known. The density of 5 liter of water is 1000kg/m³.
<h3>What is density?</h3>
The density ρ of any substance is the ratio of mass m and its volume V.
ρ = m/V
Given is the mass of water as 5 kg and the volume is 5 liter.
as, 1 L = 10−³m³
So, 5 L = 5×10−³m³
Then, density would be
ρ = 5kg / 5×10−³m³
ρ = 1000 kg/m³
Thus, the density of 5l of water is 1000kg/m³.
Learn more about density.
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