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Sonja [21]
4 years ago
6

A 1,000 of c-14 is left to decay radioactively. The half life of Carbon-14 is approximately 5,700 years. What fraction of the sa

mple will remain after 17,100 years
Physics
1 answer:
nydimaria [60]4 years ago
7 0

Answer:

none

Explanation: because 5700+5700 is 11400 and they would all die before 17100 years

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Marshall determines that a gas has a gage pressure of 276 kPa whats the absolute pressure of this gas
svlad2 [7]
The right answer for the question that is being asked and shown above is that: "<span>B: 156 kPa ." </span>Marshall determines that a gas has a gage pressure of 276 kPa whats the absolute pressure of this gas <span>B: 156 kPa </span>
3 0
3 years ago
Read 2 more answers
Air will break down (lose its insulating quality) and sparking will result if the field strength is increased to about 3 × 106 N
MrRissso [65]

Answer:

Acceleration,a=5.27\times 10^{17}\ m/s^2

Explanation:

Given that,

Electric field strength, E=3\times 10^6\ N/C

Mass of the electron, m=9.109\times 10^{-31}\ kg

Charge on electron, q=1.602\times 10^{-19}\ C

Let a is the acceleration experienced by an electron. It can be calculated as :

ma=qE

a=\dfrac{qE}{m}

a=\dfrac{1.602\times 10^{-19}\times 3\times 10^6}{9.109\times 10^{-31}}

a=5.27\times 10^{17}\ m/s^2

Hence, this is the required solution.

4 0
3 years ago
A fluid is flowing with an average speed of 1.5 m/s through a tube that has a radius of 2.0 mm and is 18 cm long. The drop in pr
Ymorist [56]

Answer:

μ = 0.038 Pa.s

Explanation:

Given that

V= 1.5 m/s

r= 2 mm

L = 18 cm

If we assume that flow inside the tube is laminar ,then the pressure drop ΔP given as

\Delta P=\dfrac{32\mu LV^2}{d^2}

\Delta P=\dfrac{32\mu LV^2}{d^2}

\mu = \dfrac{\Delta P D^2}{LV^2}

\mu = \dfrac{967\times 0.004^2}{0.18\times 1.5^2}\ Pa.s

μ = 0.038 Pa.s

The viscosity of the fluid = 0.038 Pa.s

5 0
4 years ago
A student stays at her initial position for a bit of time, then walks slowly in a straight line for a while, then stops to rest
True [87]

Answer:

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

Third interval, walk back, straight downhill

Explanation:

In this problem we have a uniform movement, this means that the acceleration in each intervals

              x = v t

 

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

Third interval, walk back, straight downhill

6 0
3 years ago
What is weightlessness ? Mention its condition​
kolbaska11 [484]

Answer:

Weightlessness, condition experienced while in free-fall, in which the effect of gravity is canceled by the inertial (e.g., centrifugal) force resulting from orbital flight. The term zero gravity is often used to describe such a condition.

5 0
3 years ago
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