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Tom [10]
3 years ago
9

An electric bell is placed inside a transparent glass jar. The bell can be turned on and off using a switch on the outside of th

e jar. A vacuum is created inside the jar by sucking out the air. Then the bell is rung using the switch. What will we see and hear?
Physics
2 answers:
Art [367]3 years ago
5 0
The answer is :  We’ll see the bell move, but we won’t hear it ring.  This is    because light can travel through vacuum but sound cannot.  Sound waves are vibrations of particles in any media, so sound requires a medium to travel, and it cannot travel in a vacuum as there is no particles to vibrate.  
qwelly [4]3 years ago
5 0
Well see the bell move but won't hear it ring
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Air bags are designed to deploy in 10 ms. Given that the air bags expand 20 cm as they deploy, estimate the acceleration of the
joja [24]

As it is given that the air bag deploy in time

t = 10 ms = 0.010 s

total distance moved by the front face of the bag

d = 20 cm = 0.20 m

Now we will use kinematics to find the acceleration

d = v_i*t + \frac{1}{2}at^2

0.20 = 0 + \frac{1}{2}a*0.010^2

0.20 = 5 * 10^{-5}* a

a = 4000 m/s^2

now as we know that

g = 10 m/s^2

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a = 400g

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The graph shows the number of beans eaten by a
il63 [147K]

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Explanation:

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What are the seven different forms of energy? Give an example of each.
wel

Answer:

Form of energy: Example

1. Light energy: Electromagnetic radiation

2. Nuclear energy: Nuclear fission

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5 0
3 years ago
Coulomb measured the deflection of sphere A when spheres A and B had equal charges and were a distance d apart. He then made the
sdas [7]

Answer:

The new distance is     d = 0.447 d₀

Explanation:

The electric out is given by Coulomb's Law

         F = k q₁ q₂ / r²

This electric force is in balance with tension.

We reduce the charge of sphere B to 1/5 of its initial value (q_{B}=q₂ = q₂ / 5) than new distance (d = n d₀)

dat

     q₁ = q_{A}

     q₂ = q_{B}

     r = d₀

In order for the deviation to maintain the electric force it should not change, so we apply the Coulomb equation for the two points

         F = k q₁ q₂ / d₀²

         F = k q₁ (q₂ / 5) / (n d₀)²

         .k q₁ q₂ / d₀² = q₁ q₂ / (5 n² d₀²)

          5 n² = 1

          n = √ 1/5

          n = 0.447

The new distance is

         d = 0.447 d₀

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3 years ago
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Answer:

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