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Tom [10]
3 years ago
9

An electric bell is placed inside a transparent glass jar. The bell can be turned on and off using a switch on the outside of th

e jar. A vacuum is created inside the jar by sucking out the air. Then the bell is rung using the switch. What will we see and hear?
Physics
2 answers:
Art [367]3 years ago
5 0
The answer is :  We’ll see the bell move, but we won’t hear it ring.  This is    because light can travel through vacuum but sound cannot.  Sound waves are vibrations of particles in any media, so sound requires a medium to travel, and it cannot travel in a vacuum as there is no particles to vibrate.  
qwelly [4]3 years ago
5 0
Well see the bell move but won't hear it ring
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Is electricity matter?<br><br> EXPLAIN.
Leokris [45]

Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.

6 0
3 years ago
Which two elements are the most abundant in the Earth's crust? A. silicon and oxygen B. silicon and magnesium C. iron and nickel
mariarad [96]

Answer: A. silicon and oxygen

Explanation:

The two most abundance elements in earth's crust are silicon and oxygen.

The most abundant element in earth's crust is Oxygen (O) which has a percentage composition of 46.6%.  Oxygen is mainly present as silicates, carbonates, sulphates etc.

The second most abundant element in earth's crust is Silicon (Si) which has a percentage composition of 27.7% . Silicon is present in the form of silicates.

The third most abundant element in earth's crust is aluminium (Al) which has a percentage composition of 8.1 %.

The fourth most abundant element in earth's crust is Iron (Fe) which has a percentage composition of 5.0 %.

7 0
3 years ago
Read 2 more answers
A wire, of length L = 4.1 mm, on a circuit board carries a current of I = 1.96 μA in the j direction. A nearby circuit element g
tamaranim1 [39]

Answer:

The magnitude of the magnetic field B is 5.921 T.

Explanation:

Given that,

Length = 4.1 mm

B_{x}=4.9\ G

B_{y}=2.3\ G

B_{z}=2.4\ G

Current I = 1.96\ mu A

We need to calculate the magnetic field

Using formula of magnetic field

B=\sqrt{B_{x}^2+B_{y}^2+B_{z}^2}

Put the value into the formula

B=\sqrt{(4.9)^2+(2.3)^2+(2.4)^2}

B=5.921\ T

Hence, The magnitude of the magnetic field B is 5.921 T.

6 0
3 years ago
Lightning is more likely to strike a metal tower than a rubber hose because:
Rudik [331]

This is because metal is a conductor of electricity while rubber is not (rubber is an insulator). Therefore the metal is more amenable to 'ground' the high charge in the lightning than rubber would. This is also why, when lightning strikes metal, it is safely 'grounded' while if it strikes a non-conductor, most occasionally, it explodes into a fire.

6 0
4 years ago
Two resistors of resistances R1 and R2, with R2&gt;R1, are connected to a voltage source with voltage V0. When the resistors are
drek231 [11]

Answer:

r=0.127

Explanation:

When  connected in series

Current = I

When connected in parallel

Current = 10 I

We know that equivalent resistance

in parallel  R= R₁R₂/(R₂+ R₁)

In series  R = R₁+R₂

Given that voltage is constant (Vo)

We also know that relationship between voltage ,current and resistance  

V = I R

Vo = I (R₁+R₂)  ------------1

Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2

From above equations

10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)  

10  R₁R₂ =  (R₁+R₂) (R₂+ R₁)

10  R₁R₂  = 2  R₁R₂  + R₁² + R₂²

8 R₁R₂  =     R₁² + R₂²

Given that

r =  R₁/R₂

Divides by R₂²

8R₁/R₂  = ( R₁/R₂)²+ 1

8 r = r ² + 1

r ² - 8 r+ 1 =0  

r= 0.127 and r= 7.87

But given that R₂>R₁  It means that r<1 only.

So the answer is r=0.127

8 0
3 years ago
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