Question

A fluid is flowing with an average speed of 1.5 m/s through a tube that has a radius of 2.0 mm and is 18 cm long. The drop in pressure is 967 Pa. What is the viscosity of the fluid?

Answer 1

Answer:

μ = 0.038 Pa.s

Explanation:

Given that

V= 1.5 m/s

r= 2 mm

L = 18 cm

If we assume that flow inside the tube is laminar ,then the pressure drop ΔP given as

$\Delta P=\dfrac{32\mu LV^2}{d^2}$

$\Delta P=\dfrac{32\mu LV^2}{d^2}$

$\mu = \dfrac{\Delta P D^2}{LV^2}$

$\mu = \dfrac{967\times 0.004^2}{0.18\times 1.5^2}\ Pa.s$

μ = 0.038 Pa.s

The viscosity of the fluid = 0.038 Pa.s