Answer:

The ratio m_2/m_1 of the masses is 9.745
Explanation:
Formula for frequency when mass m_1 is hung on the spring:

where:
k is the spring constant
Formula for frequency when mass m_2 is hung on the spring along with m_1:

where:
k is the spring constant.
In order to find ratio m_2/m_1, Divide the above equations:

On Solving the above equation:

The ratio m_2/m_1 of the masses is 9.745
Answer:
a)15077 W
b)20.2185 horse power
Explanation:
P=F*V
F=ma
a=Vf-VS/t
Vf=28m/s
t=5.2
a=28/5.2
a=5.384 m/s²
F=100kg*5.384m/s²
F=538.4 N
P=F*V
P=538.4N*28m/s
P=15077 W=20.2185 horse power
1W=0.00134 Horse power
Answer:
The size of the force developing inside the steel rod is 32039.28 N
Explanation:
Given;
length of the steel rod, L = 1.55 m
cross sectional area of the steel, A = 4.89 cm²
temperature change, ∆T = 28.0 K
coefficient of linear expansion for steel, α = 1.17 × 10⁻⁵ 1/K
Young modulus of steel, E = 200.0 GPa.
Extension of the steel is given as;
α ∆T L = FL / AE
α ∆T = F/AE
F = AEα ∆T
F = ( 4.89 x 10⁻⁴)(200 x 10⁹)(1.17 × 10⁻⁵)(28.0 K)
F = 32039.28 N
Therefore, the size of the force developing inside the steel rod when its temperature is raised, is 32039.28 N
Answer:
The change in height of the mercury is approximately 2.981 cm
Explanation:
Recall that the formula for thermal expansion in volume is:

from which we solved for the change in volume
due to a given change in temperature 
We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

Therefore, the change in volume with a change in temperature of 36°C becomes:

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):
