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Ierofanga [76]
3 years ago
9

A 500N car is pulled up to 20m plank to a flat form 5m above the ground by an effort of 150N parallel to the plank. Calculate Ve

locity Ratio?
Physics
1 answer:
Temka [501]3 years ago
5 0

Answer:

4

Explanation:

Velocity ratio is the ratio of distance moved by effort to the ratio of distance moved by load

Velocity ratio = Distance moved by effort / Distance moved by load

Distance moved by effort = 20m

Distance moved by load = 5m

20m / 5m = 4

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1 A truck covers a distance of 580km in 7 hours - Calculate<br>the velocity in km/hr​
Digiron [165]

Answer:

82.86

Explanation:

to find velocity you displacement by time

3 0
3 years ago
A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have a
Verizon [17]

Answer:

The shear deformation is \Delta x=3.34\times10^{-6}\ m.

Explanation:

Given that,

Shearing force F = 600 N

Shear modulus S = 1\times10^{9}\ N/m^2

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

S=\dfrac{Fl_{0}}{A\Delta x}

\Delta x=\dfrac{Fl_{0}}{(\dfrac{\pi d^2}{4})S}

\Delta x=\dfrac{4Fl_{0}}{\pi d^2 S}

Put the value into the formula

\Delta x=\dfrac{4\times600\times0.700\times10^{-2}}{3.14\times1\times10^{9}\times(4.00\times10^{-2})^2}

\Delta x=3.34\times10^{-6}\ m

Hence, The shear deformation is \Delta x=3.34\times10^{-6}\ m.

7 0
3 years ago
a 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.88 m/s left. afterwards, the 282 kg car
Vaselesa [24]

The momentum of the 155 kg car afterwards is 469.7 kg m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system is conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 282 kg is the mass of the bumper car

u_1 = 3.50 m/s is the initial velocity of the bumper car (we take the right as positive direction)

v_1 = 0.800 m/s is the final velocity of the bumper car

m_2 = 155 kg is the mass of the second bumper car

u_2 = -1.88 m/s is the initial velocity of the second car (moving to the left)

v_2 is the final velocity of the second car

Solving for v_2,

v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(282)(3.50)+(155)(-1.88)-(282)(0.800)}{155}=3.03 m/s

where the positive sign means the direction is to the right.

And now we can find the momentum of the 155 kg afterwards, which is

p_2 = m_2 v_2 = (155)(3.03)=469.7 kg m/s (to the right)

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
What happens to the mantle and the plates at each type of plate boundary? How can you use the materials to show what happens? *
Lilit [14]

Answer:

Explanation:

A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth's mantle to the surface, solidifying to create new oceanic crust.

7 0
3 years ago
A person pushes a block 4 m with a force of 25 N. How much work is being done?
Elina [12.6K]

Answer:

<h2>100 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 25 × 4

We have the final answer as

<h3>100 J</h3>

Hope this helps you

3 0
3 years ago
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