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My name is Ann [436]
3 years ago
14

The cheetah is one of the fastest accelerating animals, for it can go from rest to 28.0 m/s in 5.20 s. If its mass is 100 kg, de

termine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.
Physics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

a)15077 W

b)20.2185 horse power

Explanation:

P=F*V

F=ma

a=Vf-VS/t

Vf=28m/s

t=5.2

a=28/5.2

a=5.384 m/s²

F=100kg*5.384m/s²

F=538.4 N

P=F*V

P=538.4N*28m/s

P=15077 W=20.2185 horse power

1W=0.00134 Horse power

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3 years ago
What is the shortest distance between two points
White raven [17]

Answer: displacement

Explanation:

According to the definition of displacement it is the shortest distance between two points.

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3 years ago
Hii please help i’ll give brainliest if you give a correct answer please
shusha [124]

Answer:

D I think

Explanation:

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3 0
2 years ago
A rocket accelerates straight up from the ground at 12.6 m/s^2 for 11.0 s. Then the engine cuts off and the rocket enters free f
FrozenT [24]

Answer:

a) 138.6 m/s

b) 762.3 m

c) 122.3 m/s

d) 24.47

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow v=0+12.6\times 11\\\Rightarrow v=138.6 \ m/s

Velocity at the end of its upward acceleration is 138.6 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}\times 12.6\times 11^2\\\Rightarrow s=762.3\ m

Maximum height the rocket reaches is 762.3 m

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as-u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 762.3-0^2}\\\Rightarrow v=122.3\ m/s

The velocity with which the rocket crashes to the Earth is 122.3 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 762.3=0\times t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{762.3\times 2}{9.81}}\\\Rightarrow t=12.47\ s

Total time from launch to crash is 12.47+11 = 24.47 seconds

6 0
3 years ago
Superman ferma in 5,0 ∙10^(-3) s un treno inizialmente in corsa alla velocitá di 216km/h. Qual é l’accelerazione media del treno
kotykmax [81]

Answer:

1.2*10^4 m/s^2

Explanation:

The formula to find average acceleration is a=Δv/Δt.

Convert 216 km/hr to m/s

216 km/hr * 1000 m/km * 1 hr/60 mins * 1 min/60 secs = 60 m/s

So a= (60 m/s)/(5.0*10^-3) = 12000 m/s^2

Put that into scientific notation to get 1.2*10^4 m/s^2

6 0
3 years ago
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