Answer:
(a) 161.57 N
(b) 0.958 m/s^2
Explanation:
Force applied, F = 220 N
mass of crate, m = 61 kg
μ = 0.27
(a) The magnitude of the frictional force,
f = μ N
where, N is the normal reaction
N = m x g = 61 x 9.81 = 598.41 N
So, the frictional force, f = 0.27 x 598.41
f = 161.57 N
(b) Let a be the acceleration of the crate.
Fnet = F - f = 220 - 161.57
Fnet = 58.43 N
According to newton's second law
Fnet = mass x acceleration
58.43 = 61 x a
a = 0.958 m/s^2
Thus, the acceleration of the crate is 0.958 m/s^2.
Because plate movements have raised ancient sea floors above sea level, _________?
<span>Answer : Limestone that began as coral reefs can be found on the continents.</span>
Answer:
<em>c. ABBA counterbalancing
</em>
Explanation:
The student should not use the method because it is a progressive error management technique for each subject by introducing all <em>treatment circumstances twice, first in one sequence, then in the other (AB, BA) by subject counterbalancing.</em>
If participants experience conditions more than once, they experience the conditions first in one order, then the opposite order.
Answer:
Maximum acceleration will be ![1.251m/sec^2](https://tex.z-dn.net/?f=1.251m%2Fsec%5E2)
Explanation:
We have given mass of the object m = 2 kg
Spring constant k = 55.6 N/m
Amplitude is given as A = 0.045 m
We know that maximum acceleration in SHM is given by
Maximum acceleration ![=A\omega ^2](https://tex.z-dn.net/?f=%3DA%5Comega%20%5E2)
We know that ![\omega ^2=\frac{k}{m}=\frac{55.6}{2}=27.8](https://tex.z-dn.net/?f=%5Comega%20%5E2%3D%5Cfrac%7Bk%7D%7Bm%7D%3D%5Cfrac%7B55.6%7D%7B2%7D%3D27.8)
So maximum acceleration =
V=0 v²=0, A=v-u/t. T=v-u/a. T= 0-9.32/-4.06 therefore time = 2.296 seconds