All categories

2 years ago

On Earth's surface, the weight of an object equals the product of its mass and _____.

Physics

1 answer:

Lilit [14]2 years ago

6 0

F. The magnitude of the net force acting on the object.

You might be interested in

What is most likely the author’s motive for writing this article? to get you to buy sports products to get you to support nuclea

harina [27]

To get you to aooreciate the benefits of atomic reaserch

i know this cause i just had the question and i got it right

4 0

3 years ago

Read 2 more answers

A positive charge of 1 µC is taken from points A & B such that VA-VB = 100 V. Then the

Lunna [17]

Explanation:

It is given that,

Let Charge of $1\ \mu C$ is taken from points A & B such that $V_A-V_B=1000\ V$ .

We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

$W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J$

So, the energy of charge decreases by $10^{-3}\ J$ . Hence, the correct option is (a).

4 0

2 years ago

A metal rod 80cm long lengthens by 0.090cm when its temperature rises by 93.6$^o$C. What is the linear expansivity of the metal

alexandr1967 [171]

Answer: (b)0.000012/k

Explanation:

The linear expansion of the metal rod is given by

$\Delta L= L_0 \alpha \Delta T$

where

$\Delta L=0.090 cm$ is the linear expansion

$L_0 = 80 cm$ is the initial length of the rod

$\alpha$ is the linear expansivity

$\Delta T=93.6^{\circ}C=93.6 K$ is the increase in temperature

By re-arranging the equation, we find the linear expansivity:

$\alpha = \frac{\Delta L}{L_0 \Delta T}=\frac{0.090 cm}{(80 cm)(93.6K)}=0.000012 K^{-1}$

8 0

3 years ago

A heat engine operates between two reservoirs at 300K. During each cycle, it absorbs 200 calories from the high temperature rese

yanalaym [24]

(a) Zero

The maximum efficiency (Carnot efficiency) of a heat engine is given by

$\eta=1-\frac{T_C}{T_H}$

where

$T_C$ is the low-temperature reservoir

$T_H$ is the high-temperature reservoir

For the heat engine in the problem, we have:

$T_C = 300K$

$T_H = 300K$

Therefore, the maximum efficiency is

$\eta=1-\frac{300}{300}=0$

(b) Zero

The efficiency of a heat engine can also be rewritten as

$\eta = \frac{W}{Q_H}$

where

W is the work performed by the engine

$Q_H$ is the heat absorbed from the high-temperature reservoir

In this problem, we know

$\eta=0$

Therefore, since the term $Q_H$ cannot be equal to infinity, the numerator of the fraction must be zero as well, which means

W = 0

So the engine cannot perform any work.

5 0

2 years ago

Identify the charge(s) with increasing electric potential energy.

kap26 [50]

Cznxjsjssbsishsisbsisbsisbsbeoeb

4 0

2 years ago