Answer:
The mass density of the string is (0.3/L)kg/m
Explanation:
Mass density of the string = Mass/Length
Mass = 0.3kg
The length of the string is unknown so it is assumed to be L meter(s)
Therefore, mass deny of the string = 0.3kg/Lm = (0.3/L)kg/m
Answer:last choice is correct. Work is equally to force times distance
Explanation:to generalize, W is equal to to force as a function of distance integrated over distance. Work is equivilent to energy. See work/force equivalency
Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.
Answer:
v = 40 [m/s].
Explanation:
Linear momentum is defined as the product of mass by Velocity. In this way, by means of the following equation, we can calculate the momentum.

where:
m = mass [kg]
v = velocity [m/s]
![P =20*10\\P =200 [kg*m/s]](https://tex.z-dn.net/?f=P%20%3D20%2A10%5C%5CP%20%3D200%20%5Bkg%2Am%2Fs%5D)
Since all momentum is transferred, we can say that this momentum is equal for the mass of 5 [kg]. In this way, we can determine the speed after the impact.
![v = P/m\\v = 200/5\\v = 40 [m/s]](https://tex.z-dn.net/?f=v%20%3D%20P%2Fm%5C%5Cv%20%3D%20200%2F5%5C%5Cv%20%3D%2040%20%5Bm%2Fs%5D)
Answer:
The magnitude of the lift force L = 92.12 kN
The required angle is ≅ 16.35°
Explanation:
From the given information:
mass of the airplane = 9010 kg
radius of the airplane R = 9.77 mi
period T = 0.129 hours = (0.129 × 3600) secs
= 464.4 secs
The angular speed can be determined by using the expression:
ω = 2π / T
ω = 2 π/ 464.4
ω = 0.01353 rad/sec
The direction 

θ = 16.35°
The magnitude of the lift force L = mg ÷ Cos(θ)
L = (9010 × 9.81) ÷ Cos(16.35)
L = 88388.1 ÷ 0.9596
L = 92109.32 N
L = 92.12 kN