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4 years ago

HELP PLEASE!Can anyone help with any of these?

Physics

1 answer:

nadezda [96]4 years ago

6 0

1. The magnitude is 49.00 meters and his direction is 7.43 degrees to the right of his original position.

2. D = 7.7 km at 26.2° to ground ANS

3. 172 km

4. 172 km in a direction 34.2 degrees East of North

<em>I hope this helps you!!!</em>

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How do materials, such as nutrients and waste, pass through the cell membrane?

Aleks04 [339]

Think of the cell membrane as a net and the nutrients are the perfect fit to fall through it. Where the waste is not the right size and will not fit through the holes of the net.

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4 years ago

A highway curves to the left with radius of curvature of 36 m and is banked at 28 ◦ so that cars can take this curve at higher s

iVinArrow [24]

Answer: 30.34m/s

Explanation:

The sum of forces in the y direction 0 = N cos 28 - μN sin28 - mg

Sum of forces in the x direction

mv²/r = N sin 28 + μN cos 28

mv²/r = N(sin 28 + μcos 28)

Thus,

mv²/r = mg [(sin 28 + μ cos 28)/(cos 28 - μ sin 28)]

v²/r = g [(sin 28 + μ cos 28)/(cos 28 - μ sin 28)]

v²/36 = 9.8 [(0.4695 + 0.87*0.8829) - (0.8829 - 0.87*0.4695)]

v²/36 = 9.8 [(0.4695 + 0.7681) / (0.8829 - 0.4085)]

v²/36 = 9.8 (1.2376/0.4744)

v²/36 = 9.8 * 2.6088

v²/36 = 25.57

v² = 920.52

v = 30.34m/s

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4 years ago

If citizens do not fulfill their responsibilities to pay taxes in a timely manner, the US government will be unable to do which

Paha777 [63]

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3 years ago

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4 years ago

What are four factors that can affect the amount of friction between two objects

umka2103 [35]

As the Force of friction is equal to $F _{f} =$ µ $F_{n}$ by using the Law of Action Reaction; as the force normal is the conterforce of gravity

$F _{f} =$ µ $F_{n}$
$F_{f}=$ µ $F_{n}$

Therefore, by looking at the equation we can infer that

The force of friction is directly proportional to the mass, gravitational constant, and the co-efficent of friction

Because the gravitational constant is dependant on gravitation, a planet's mass and radius also affect the force of friction

But DO NOTE:
That the co-effecient of friction is only applicable between two rubbing surfaces and unaffected by gravitational constants.

If you found this helpful, please rate it as "Brainiest"
Also if this need further explaining, please comment below

7 0

4 years ago