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2 years ago

Please help!!!! im stuck on this oneeeeeeeeeeeeee and also explain

Mathematics

2 answers:

mestny [16]2 years ago

5 0

Answer: B. 3n + 9

Step-by-step explanation:

there are 3 with an unknown value so it is 3n and there are 9 pieces that are each equal to 1 witch makes it 3n+9. hope this helps have a good day

musickatia [10]2 years ago

4 0

The answer is b! 3n+9

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The regular selling price of a pair of men's jeans is $39.99. The markdown rate is 20%. What is the sale price of the jeans to t

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Take the original price, multiply it by 20% (you have to move the decimal place two to the left, so it becomes .2), then subtract the answer from the original price.
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If you wanted to, you could also round the $7.998 to $8.00. Your answer would be the same.

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2 years ago

What is the slope of the line in the graph?

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Answer:

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2 years ago

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Students received grades with or - (example B ). Of all students who received one or more plus grades, 92% were undergraduates a

MrMuchimi

Answer:

The probability that a student is an undergraduate student, given that the student received a plus grade is 0.92

Step-by-step explanation:

The conditional probability of an event B given that another event A has already occurred is:

$P(B|A)=\frac{P(A\cap B)}{P(A)}$

Denote the events as follows:

X = a students is a graduate

Y = a students is a under-graduate

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According to the tree diagram, the probability that a student is an undergraduate student, given that the student received a plus grade is:

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Thus, the probability that a student is an undergraduate student, given that the student received a plus grade is 0.92.

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2 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

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The bounded area is 5 + 5/6 square units.

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