The blackbox recorder from an airplane that hit a patch of severe turbulence indicated that the plane moved up and down with an
1 answer:
Answer:
T = 8.19 s
, = 23 m / s
Explanation:
In the simple harmonic motion the equation that describes them is
y = A cos wt
Acceleration can be found by derivatives
a = d²y / dt²
v = dy / dt = - Aw sin wt
a= d²y / dt² = - A w² cos wt
For maximum acceleration cosWT = + -1
= -A w2
w = RA (/ A)
w = RA (1.8 9.8 / 30.0)
w = 0.767 rad / s
The angular velocity is related to the frequency
w = 2π f
f = 1 / T
w = 2π / T
T = 2π / w
T = 2π / 0.767
T = 8.19 s
For maximum speed the sin wt = + -1
= A w
= 30.0 0.767
= 23 m / s
You might be interested in
The definition of energy and simple harmonic motion we can find the result for the point at which the kinetic energy and potential energy are equal is:
θ = 9.8º
The mechanical energy is the sum of the kinetic energy and the potential energies, in the case that there is no friction, this energy is constant and gives advantage to one of the most important principles of physics.
The kinetic energy is: K = ½ m v²
The potential energy is: U = m g (y-y₀)
The mechanical energy is Em = K + U
Where m is mass, v is linear velocity, g is the acceleration of gravity, y height.
The simple pendulum is a simple harmonic system that for small angles has a shape solution.
θ = θ₀ cos (wt + Ф)
where θ is the angle of motion, w is the angular velocity t time and Ф a phase constant that depends on the initial conditions.
They indicate that the system that has a length of l = 1.0 m, is released at the angle of θ₀ = 20º (π rad / 180º) = 0.349 rad, remember that in the rotation movement all the angles must be in radian, let's look for the initial constant.
Velocity is defined by the change in position or angles with respect to time.
w = = -θ₀ w sin (wt + Ф)
At the initial movement for time t = 0 the velocity is zero
0 = - θ₀ w sin Ф
For the equality to be correct, the sine function must be zero, which implies that the phase angle are zero Ф = 0, therefore the solution for the angle and the velocity are:
θ = θ₀ cos wt
w = - θ₀ w sin wt
The angular velocity is given by the relation
w² = g / l
we calculate
w =
w = 3.13 rad / s
let's look for the expression for the energies.
K = ½ m v²
Linear and angular variables are related.
v = w l
We substitute
K = ½ m l² w²
We substitute the expression for the angular velocity.
K = ½ m l² ( -θ₀ w sin wt) ²
We look for the potential energy, where we make the initial height zero.
U = m g θ₀ cos wt
Ask the point where kinetic energy and potential energy are equal.
K = U
½ m l² θ₀² w² sin² wt = m g θ₀ cos wt
θ = wt
Let's calculate.
sin² θ = 5.73 cos θ
The solution of
θ' = 1.4 + 2π n n= 0, 1, 2, ...
First occurs for n = 0
θ = 1.40 rad = 80.2º
This solution is the angle is measured from the horizontal, therefore the angle measured from the vertical corresponds:
θ = 90- 8.02
θ = 9.8º
In conclusion using the definition of energy and simple harmonic motion we can find the result for the point at which the kinetic energy and potential energy are equal is:
θ = 9.8º
Learn more here: brainly.com/question/17315536
Faraday's law of induction states the following:
The strength of the induced electromotive force is equal to the negative of the time rate of change of the magnetic flux enclosed by the circuit.
Knowing all this, we can conclude that the answer is C.
Flux can be understood as the number of field lines interesting with the area of the loop. You can simply think that stronger field has more field lines. This is just a useful simplification.
When you simply move the loop along the lines of magnetic field there is no change in flux. If you are rotating or moving the loop in and out of the field you are changing the are of the loop that intersects with the field and thus you are changing the flux. The same thing happens when you have a changing field, the only difference being that field is doing all the work for you.
The strength of the induced electromotive force is equal to the negative of the time rate of change of the magnetic flux enclosed by the circuit.
Knowing all this, we can conclude that the answer is C.
Flux can be understood as the number of field lines interesting with the area of the loop. You can simply think that stronger field has more field lines. This is just a useful simplification.
When you simply move the loop along the lines of magnetic field there is no change in flux. If you are rotating or moving the loop in and out of the field you are changing the are of the loop that intersects with the field and thus you are changing the flux. The same thing happens when you have a changing field, the only difference being that field is doing all the work for you.