The troposphere protect the molecules because there are higher layers on top. This makes life possible on Earth.
Answer:
Answer of question a is 345J.
Explanation:
In question a following is given in data:
-mass of iron (m) = 10.0 g
-temperature (ΔT) = final temperature- initial temperature= 100-25= 75 degree Celsius
-Specific Heat capacity of iron (c)= 0.46J/g°C.
Heat (Q)=?
Solution:
Formula for Heat is :
Q=m x c x ΔT
Q= 10 x 0.46 x 75
Q= 345 J.
so, 345 joules of heat is needed to increase the temperature of 10 grams of iron.
- From the above formula all other questions can easily be solved from the same procedure.
Answer:
You manage to find a bottle of bromothymol blue and a few extra beakers. You take one of the empty beakers and add some of the first unlabeled solution and some indicator.
The color changes to yellow.
You then add some solution from the other unlabeled flask into this beaker and see the color change to blue.
What are the identities of each unlabeled solution?
Explanation:
Bromothymol blue is a dye and it is used as an indicator.
It is used as a pH indicator.
In acids, it becomes yellow n in color.
In bases, it turns blue.
You take one of the empty beakers and add some of the first unlabeled solution and some indicator. The color changes to yellow.
That means the unlabeled solution is an acid.
You then add some solution from the other unlabeled flask into this beaker and see the color change to blue.
It is a basic solution.
Answer:
375.2 kJ
Explanation:
- H₂(g) +F₂(g) → 2HF(g) +536kJ
The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.
We can then <u>state a rule of three</u>:
And <u>solve for X</u>:
- X = 1.4 mol * 536 kJ / 2 mol
Using ideal gas formula (PV=nRT), you can conclude that volume directly related to the temperature. That means an increase in temperature will cause an increased volume too. Note that the temperature is using Kelvin, not Celsius. The calculation would be:
V1/T1= V2/T2
590ml / (-<span>55+ 273)K = V2/ (30+273)K
V2= (590ml/ 218K) * 303K
V2= 820ml</span>
