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Leviafan [203]
3 years ago
5

Circle which of the following depend on the amount of matter present:

Chemistry
1 answer:
yan [13]3 years ago
4 0
It is the boilimg point now aa
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Calculate the number of atoms of argon in 75.0 L of argon at STP.<br> ?????
charle [14.2K]
Quero pontos mesmo veu que cu descylapa moçe
5 0
3 years ago
33.23 grams of a thin sheet of iron is completely oxidized in 7 days. How would you express the rate of conversion of the silver
tresset_1 [31]

Answer:

A. 0.0440 moles/day

Explanation:

First, let's figure out how many moles 33.23 grams of silver is. We do this by dividing the number of grams by the molar mass of silver, which is 107.87 g/mol:

33.23 g Ag ÷ 107.87 g/mol = 0.3081 mol Ag

Now, let's divide this by 7 to get the rate per day:

0.3081 mol Ag ÷ 7 days = 0.0440 mol/day

Thus, the answer is A.

7 0
3 years ago
What is the oxidation number of boron in Na(B(NO3)4)
Vitek1552 [10]

Answer:

the oxidation state od boron in sodium boron hydride is (+3).

7 0
1 year ago
Read 2 more answers
When 25.0 mL of a solution of 1.4 x 10-3 M silver nitrate is mixed with 60.0 mL of a solution of 7.5 x 10-4 M sodium chloride a)
LUCKY_DIMON [66]
Step  one write  the  equation  for  dissociation  of  AgNO3  and  NaCl

that  is   AgNO3-------> Ag+   + NO3-

            NaCl-------->   Na+   +  Cl-
then  find  the  number  of  moles  of  each  compound
that  is  for   AgNO3  = ( 1.4 x10^-3 ) x  25/1000=  3.5  x10^-5  moles
                     Nacl=  (7.5  x10^-4)x 60/1000=  4.5  x10^-5  moles

from   mole  ratio  the  moles  of    Ag+=  3.5  x10^-5 moles  and  that  of  Cl-= 4.5  x10^-4 moles

  then find  the  total    volume  of  the  mixture
that  is  25ml  +  60 Ml  =85ml  =  0.085 liters

The  Ksp  of  Agcl =  (Ag+) (cl-),    let  the  concentration  of  Ag+ be  represented   by  x  and   also  the  concentration  be  represented by  x

ksp (1.8 x10^-10)  is  therefore=  x^2

find  the  square  root   x=1.342   x10^-5

Ag+ in  final  mixture  is =  moles  of  Ag+/total  volume - x
that is  {(3.5  x10^-5)/0.085}  -  1.342  x10^-5=3.98x10^-4


Cl-  in  the  final  mixture   is =(4.5  x10^-5 /0.085)  -  1.342  x10^-5= 5.16 x10^-4
4 0
3 years ago
Read 2 more answers
Water flows over Niagara Falls at the average rate of 2,400,000 kg/s, and the average height of the falls is about 50 m. Knowing
Andre45 [30]

Answer:

Power, P=1.176\times 10^9\ W

No of bulbs = 78400000

Explanation:

We have,

Water flows over Niagara Falls at the average rate of 2,400,000 kg/s, it mean it is mass per unit time i.e. m/t.

It falls from a height of 50 m

The gravitational potential energy of falling water is given by :

P = mgh

Power is equal to the work done divided by time taken. So,

P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{m}{t}\times gh

So,

P=2400000\times 9.8\times 50\\\\P=1.176\times 10^9\ W

Let there are n bulbs that could power 15 W LED. It can be calculated by dividing the power by 15. So,

n=\dfrac{1.176\times 10^9}{15}\\\\n=78400000\ \text{bulbs}

It means that the number of bulbs are 78400000.

3 0
3 years ago
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