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3 years ago

The percentage by mass of Br in the compound

2 answers:

8 0

What you have to do it find the percentage / solve it. Divide the mass by the entire mass.
<span>239.7 </span>÷<span> 266.68 = 0.898 </span>×<span> 100 = 90% Br.</span>

Sholpan [36]3 years ago

6 0

Answer: The correct answer is option(4).

Explanation:

Molar mass of the aluminium bromide, $AlBr_3=266.69 g/mol$

Atomic mass of bromine = 79.90 g/mol

Percentage of Mass of bromine in $AlBr_3$ :

$\% Br\text{ by mass}=\frac{\text{Atomic mass of Br}\times \text{Number of Br atoms}\times 100}{\text{Molar mass of }AlBr_3}$

$\% Br\text{ by mass}=\frac{79.90 g/mol\times 3\times 100}{266.69 g/mol}=89.97\%\approx 90\%$

Hence, the correct answer is option(4).

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melisa1 [442]

Answer:

Farther, longer, longer

Explanation:

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8 0

2 years ago

How many grams are in 3.14 moles of PI₃?

OverLord2011 [107]

Answer:

$\boxed {\boxed {\sf 1290 \ g \ PI_3}}$

Explanation:

We want to convert from moles to grams, so we must use the molar mass.

<h3>1. Molar Mass</h3>

The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.

Phosphorus (P): 30.973762 g/mol
Iodine (I): 126.9045 g/mol

Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.

I₃: 126.9045 * 3=380.7135 g/mol

PI₃: 30.973762 + 380.7135 = 411.687262 g/mol

<h3>2. Convert Moles to Grams</h3>

Use the molar mass as a ratio.

$\frac {411.687262 \ g \ PI_3}{ 1 \ mol \ PI_3}$

We want to convert 3.14 moles to grams, so we multiply by that value.

$3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \ mol \ PI_3}$

The units of moles of PI₃ cancel.

$3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }$

$1292.698 \ g\ PI_3$

<h3>3. Round</h3>

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.

1292.698

The 2 in the ones place tells us to leave the 9.

$1290 \ g \ PI_3$

3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>

4 0

2 years ago

The chemical equation may not be balanced with HCI + NaOH

Masja [62]

Answer:

idk

Explanation:

3 0

2 years ago

If gas in a sealed container has a pressure of 50 kPa at 300 K, what will the pressure be if the temperature rises to 360 K?

VLD [36.1K]

The answer is 60 kpa, also did you try look it up because that is what i did but i did not copy and paste it.

hope this helped have a good day

6 0

3 years ago

What is the molar solubility of agcl in 0. 30 m nacl at 25°C. ksp for agcl is 1. 77 × 10^-10.

Rzqust [24]

Molar solubility of AgCl will be 0.59 × $10^{-10}$ M.

The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.

A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.

Calculation of molar solubility:

Given data:

M = 0.30 M

$K_{sp}$ = 1.77 × $10^{-10}$