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3 years ago

Which equation is mostly likely used to determine the acceleration from a velocity vs time graph

Physics

2 answers:

Keith_Richards [23]3 years ago

6 0

Most likely, the equation is

Acceleration over a period of time =

(change in speed during the period of time)

divided by

(length of the period of time) .

for any piece of the graph.

Wewaii [24]3 years ago

4 0

The slope (m) of the graph is most likely used to determine the acceleration from a velocity vs time graph.

Explanation:

Acceleration is referred as the ratio of velocity with respect to time traveled by the object. The formula to find out slope of the graph = (y2 - y1) / (x2 - x1).

To find the acceleration, calculate the slope of the graph as it will denote the acceleration. When the slope of the graph is zero, it means the acceleration of the object is zero and when it is positive, the acceleration is positive.

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A sportsman can develop a maximum speed of 12 m/s when he is swimming in a pool. Calculate the time that is required to travel a

kumpel [21]

Answer:

0.48

Explanation:

12m/s

(m/s)

Speed=12

meters=25

25÷12=0.48

6 0

3 years ago

Read 2 more answers

I don’t understand this question

hichkok12 [17]

It's Z.

Without any force acting on it an object travels in a straight line.

In order to bend away from a straight line the object needs a force acting on it.

In order to move along a circle, the force on the object points toward the center of the circle. It's called the centripetal force.

Since the object's direction is changing it has acceleration.

The acceleration points toward the center of the circle.

6 0

3 years ago

Determine the elastic energy U stored in the compressed spring.

hoa [83]

Answer:

Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.

Explanation:

7 0

3 years ago

The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N

Hunter-Best [27]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g = 1.63 $m/s^2$

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

$Weight=72 kg\times 1.63m/s^2=117.36 N$

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

5 0

4 years ago

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Two 800 cm^3 containers hold identical amounts of a monatomic gas at 20Â°C. Container A is rigid. Container B has a 100 cm^2 pis

Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

Given that;

Temperature = 20°C = 293 K

mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

Final Temperature of the gas in A will b GREATER than the temperature in B

Diagram of both processes on a single PV has been uploaded below,

Initial pressures in containers A and B

PV = nRT

P = RT/V

we substitute

P = (8.3 × 293) / 0.8

P = 2431.9 / 0.8

P = 3039.87 J/liters

Therefore, The Initial pressures in containers A and B is 3039.87 J/liters

Given that;

power = 25 W

time t = 15s

the final volume of container B = ?

we know that;

work done = power × time

work done = 25 × 15 = 375

Also work done = P( V₂ - V₁ )

so we substitute

375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

Therefore, the final volume of container B is 923.36 cm³

7 0

3 years ago