Answer:
The frictional torque is 
Explanation:
From the question we are told that
The mass attached to one end the string is 
The mass attached to the other end of the string is 
The radius of the disk is 
At equilibrium the tension on the string due to the first mass is mathematically represented as
substituting values
At equilibrium the tension on the string due to the mass is mathematically represented as
The frictional torque that must be exerted is mathematically represented as
substituting values
In some unusual applications of unusual components, I can think of unusual electric circuits where a switch may be connected in parallel with a device in order to control it.
But I'm sure this is not what's intended in a question on the high-school level.
Until you get in a situation with tricky applications in a tricky circuit, your switches will always be connect <em>in series</em> with the devices they control.
Answer:
the car with the hay should slow to 16m/s if the bale of hay is dropped into it.
Let t = Theta and p = Phi
Tan t = y/x Then x =y/Tant.
Tant = y/(x-d) x-d = y/Tanp
y/Tant - d = y/Tanp
y -d*Tanr = y*Tant/Tanp
y-y*Tant/Tanp = d*Tanr
y(1 - Tanr/Tanp = d*Tant
y = d*Tant/(1-Tant/Tanp)
Answer:
stress = 16.9 MPa
Explanation:
The stress in the cable can be calculated as:
Where F is the force and A is the area. So, the area can be calculated as:
Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:
Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:
Therefore, the answer is 16.9 MPa
