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atroni [7]
3 years ago
10

A scientist is observing a eukarotic cell and a prokaryotic cell. Which structure could she only observe in the eukaryotic cell?

Physics
2 answers:
Ksenya-84 [330]3 years ago
7 0
The answer is nucleus
tangare [24]3 years ago
4 0

Answer:

It's definitely Nucleus

Hope this Helps!

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D is the correct answer!

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What would happen happen if a car crashes​
Ierofanga [76]

Answer:

Your body just being crushed from the side. With a side-impact we see much more severe injuries to the thorax and upper-body; you get a lot more rib fractures; a lot more damage to the lungs and internal organs because of the side-impact.

Explanation:

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8 0
3 years ago
A 10-KG cart moving at 5 m/s collides with a 5 KG cart at rest and causes it to move 10 m/s. Which principal explains the result
IgorLugansk [536]

Answer: energy transfer. or, kinetic energy.

Explanation:

when something collides with another, it transfers kinetic energy to the other it collided with, making it move.

5 0
3 years ago
A ball that is attached to a string travels in a horizontal, circular path, as shown in Figure 1. At time t0 , the ball has a sp
Levart [38]

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r   --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

F₁ = 4 mv₀²/r

using equation (1):

<u>F₁ = 4 F₀</u>

5 0
4 years ago
A parallel plate capacitor is constructed with a dielectric slab with κ = 1.5 inserted between the plates. The area of each plat
maksim [4K]

Answer:

The value is V =  4.533  \  V

Explanation:

From the question we are told that

The dielectric constant is k = 1.5

The area of each plate is A =  5 \ cm^2 = 0.0005 m^2

The distance between the plates is d= 1 \  mm  =  0.001 \  m

The charge on the capacitor is Q =  6*10^{-11} \  C

Generally the electric field in a vacuum is mathematically represented as

E_o  =  \frac{V_o}{d}

Generally V_o is the voltage of the capacitor which is mathematically represented as

V_o =  \frac{Q}{C_o}

Here C_o is the capacitance of the capacitor in a vacuum which is mathematically represented as

C_o =  \frac{\epsilon_o * A}{d}

Here epsilon_o is a constant with value epsilon_o= 8.85*10^{-12} C^2 \cdot N^{-1} \cdot m^{-2}

=> C_o =  \frac{8.85*10^{-12} * 0.0005 }{0.001}

=> C_o =  4.425 *10^{-12}  \  F

So

V_o =  \frac{6*10^{-11} }{  4.425 *10^{-12}}

V_o =  13.6 \  V

So

E_o  =  \frac{ 13.6}{0.001}

=> E_o  = 13600 \ V/m

The electric field when the dielectric slab is inserted is mathematically represented as

E =  \frac{E_o}{k}

=> E =  \frac{13600}{1.5}

=> E =9067  \ V/m

Generally the electric field between the plates is mathematically evaluated as

E_{N} =  E_o - E

=> E_{N} =  13600- 9067

=> E_{N} = 4533 \  V/m

Generally the potential difference between the plates is

V =  4533   *  0.001

=> V =  4.533  \  V

6 0
4 years ago
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