Answer:
113 g NaCl
Explanation:
The Ideal Gas Law equation is:
PV = nRT
In this equation,
> P = pressure (atm)
> V = volume (L)
> n = number of moles
> R = 8.314 (constant)
> T = temperature (K)
The given values all have to due with the conditions fo F₂. You have been given values for all of the variables but moles F₂. Therefore, to find moles F₂, plug each of the values into the Ideal Gas Law equation and simplify.
(1.50 atm)(15.0 L) = n(8.314)(280. K)
2250 = n(2327.92)
0.967 moles F₂ = n
Using the Ideal Gas Law, we determined that the moles of F₂ is 0.967 moles. Now, to find the mass of NaCl that can react with F₂, you need to (1) convert moles F₂ to moles NaCl (via the mole-to-mole ratio using the reaction coefficients) and then (2) convert moles NaCl to grams NaCl (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).
1 F₂ + 2 NaCl ---> Cl₂ + 2NaF
Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl): 58.44 g/mol
0.967 moles F₂ 2 moles NaCl 58.44 g
---------------------- x ----------------------- x ----------------------- = 113 g NaCl
1 mole F₂ 1 mole NaCl
Chemical change because this not the same
Answer:
The answer for number one is .A
The answer for number two is heat rises
Explanation:
Answer:
The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule
Explanation:
Isotopic labeling is a common method for deducing reaction mechanism in chemistry.
In photosynthesis, the oxygen in the found in Glyceraldehyde-3-Phosphate comes from the carbon dioxide, This is also finally found in the glucose produced at the end of the cycle.
The oxygen in water is released into the atmosphere as the oxygen molecule.
Therefore, the C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule.