B is true since evaporation changes a liquid into a gas and dondensation turns a gas into a liquid
Sodium is in group 1 so it has 1 valence electron (one electron in its outer shell). Sodium will be looking to lose its one valence electron in order to become more stable. Chlorine is in group 17 so it has 7 valence electrons, and therefor only needs to gain one valence electron to attain noble gas electron configuration (become stable with 8 valence electrons, just like the noble gases in group 18 have 8). Because the chlorine atom is trying to gain one electron, and the sodium atom is trying to lose one, sodium will give up its one valence electron to chlorine and the two atoms will form an ionic bond. Because chlorine is looking to gain just one electron and sodium is looking to lose the same number, the ratio of chlorine atoms to sodium atoms will be 1:1, one chlorine atom per one sodium atom.
Answer:
Four significant figures.
Explanation:
Hello,
In this case, considering that the measurement 16.08 L has four digits we must take into account that all are significant even the zero due to fact that is to the right of the first nonzero digit which is 1, therefore, the measurement has four significant figures.
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Answer:
Keq = 0.053
7.3 kJ/mol
Explanation:
Let's consider the following isomerization reaction.
glucose 6‑phosphate ⇄ glucose 1 - phosphate
The concentrations at equilibrium are:
[G6P] = 0.19 M
[G1P] = 0.01 M
The concentration equilibrium constant (Keq) is:
Keq = [G1P] / [G6P]
Keq = 0.01 / 0.19
Keq = 0.053
We can find the standard free energy change, ΔG°, of the reaction mixture using the following expression.
ΔG° = -R × T × lnKeq
ΔG° = -8.314 J/mol.K × 298 K × ln0.053
ΔG° = 7.3 × 10³ J/mol = 7.3 kJ/mol
Answer:
The Answer is C. 550 milliliters
