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3 years ago

Calculate the mass percentages of carbon hydrogen and oxygen in sucrose

1 answer:

3 0

The formula for sucrose is C12H22O11 with a molecular mass of approx 342g/mol
% mass of C = 12(12) / 342 × 100% = 42.1%
% mass of H = 22(1) / 342 × 100% = 6.43%
% mass of O = 11(16) / 342 ×100% = 51.5%

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What are the general properties of the elements in the first two groups on the right side of the modern periodic table?

telo118 [61]

They have free electron(s) on their outermost energy levels making them good conductors.
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3 years ago

A block of pine wood has a mass of 120 g and a volume of 300 cm3. What is the density of wood? (Show your work)

Zielflug [23.3K]

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume}$

From the question

mass of wood = 120 g

volume = 300 cm³

So the density of the wood is

$density = \frac{120}{300} \\ = \frac{12}{30} = \frac{2}{5}$

We have the final answer as

Hope this helps you

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3 years ago

If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?

myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30.17}\ year^{-1}$

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Initial concentration $[A_0]$ = ?

Final concentration $[A_t]$ = 12.5 grams

Applying in the above equation, we get that:-

$12.5\ g=[A_0]e^{-0.02297\times 90.6}$

$[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g$

<u>Mass of original sample = 100 g</u>

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2 years ago

Why are fibers birefringent

horrorfan [7]

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3 years ago

Read 2 more answers

What is the ratio of mass of 0.7moles of nitrogen gas to 11.2liters of oxigen gas at STP?

Airida [17]

Answer:

if a 40.0-gram sample of the gas occupies 11.2 liters of space at STP? A balloon is filled with 5 moles of helium gas.

Explanation:

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3 years ago