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Akimi4 [234]
3 years ago
8

If 0.25 moles of KBr is dissolved in 0.5 liters of

Chemistry
1 answer:
Len [333]3 years ago
6 0

Answer:

[KBr] = 454.5 m

Explanation:

m is a sort of concentration that indicates the moles of solute which are contianed in 1kg of solvent.

In this case, the moles of solute are 0.25 moles.

Let's determine the mass of solvent in kg.

Density of heavy water, solvent, is 1.1 g/L and our volume is 0.5L.

1.1 g = mass of solvent / 0.5L, according to density.

mass of solvent = 0.5L . 1.1g/L = 0.55 g

We convert the mass to kg → 0.55 g . 1kg /1000g = 5.5×10⁻⁴ kg

m = mol/kg → 0.25 mol /5.5×10⁻⁴ kg = 454.5 m

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Convert 9.32x 10 23ª atoms of au to moles of au
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Answer:

\huge\boxed{\sf no.\ of\ moles = 1.55\ moles }

Explanation:

<u>Given:</u>

Number of atoms = 9.32 \times 10^{23} atoms

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<u>Required:</u>

Moles = ?

<u>Formula:</u>

\displaystyle No.\ of\ moles = \frac{no. \ of \ atoms }{avogadro's \ no.}

<u>Solution:</u>

\displaystyle no. \ of \ moles = \frac{9.32\times 10^{23}}{6.023 \times 10^{23}}

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\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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