All categories

3 years ago

If 0.25 moles of KBr is dissolved in 0.5 liters of

Chemistry

1 answer:

Len [333]3 years ago

6 0

Answer:

[KBr] = 454.5 m

Explanation:

m is a sort of concentration that indicates the moles of solute which are contianed in 1kg of solvent.

In this case, the moles of solute are 0.25 moles.

Let's determine the mass of solvent in kg.

Density of heavy water, solvent, is 1.1 g/L and our volume is 0.5L.

1.1 g = mass of solvent / 0.5L, according to density.

mass of solvent = 0.5L . 1.1g/L = 0.55 g

We convert the mass to kg → 0.55 g . 1kg /1000g = 5.5×10⁻⁴ kg

m = mol/kg → 0.25 mol /5.5×10⁻⁴ kg = 454.5 m

You might be interested in

You run an experiment in which two substances chemically react in a closed system. you run the same experiment in an open system

m_a_m_a [10]

If we run an experiment in which two substances chemically react in a closed system and then we run the same experiment in an open system, then the masses of the products in each experiment will be different because the open system allows the interchange of matter and energy with the media.

<h3>What is an open system?</h3>

An open system is an interrelated group pf parts that work together to interchange matter and energy with the surrounding environment, while a closed system does not generate an exchange of matter and energy.

Therefore, with this data, we can see that an open system interchange energy and matter with the environment, while closes systems do it.

Learn more about open systems here:

brainly.com/question/28891854

#SPJ1

6 0

1 year ago

Which do you think has more mass, 1 mole of fructose, 1 mole of sucrose or 1 mole of aspartame? Explain your reasoning.

pogonyaev

Answer:

i think they would be all the same

Explanation:

they sound like sugars

6 0

3 years ago

Read 2 more answers

Match each statement with one of these terms.

skelet666 [1.2K]

Answer:

1 - e, 2 - k, 3 - a, 4 - i, 5 - b,

Explanation:

The ratio of the amount of analyte in the stationary phase to the amount in the mobile phase. --- Retention factor.

Time it takes after sample injection into the column for the analyte peak to appear as it exits the column. -- Retention time

The process of extracting a component that is adsorbed to a given material by use of an appropriate solvent system. -- Elution

Measure of chromatographic column efficiency. The greater its value, the more efficient the column. -- Theoretical plate number

Gas, liquid, or supercritical fluid used to transport the sample in chromatographic separations. -- Mobile phase

Immiscible and immobile, it is packed within a column or coated on a solid surface. -- Stationary phase

8 0

3 years ago

How would you represent the atoms of aluminum in the gaseous phase

bezimeni [28]

Gaseous phase have no system and are more widespread than other states.

3 0

3 years ago

If 5.12 g of oxygen O2 gas occupies a volume of 6.21L at a certain temperature and pressure, how many grams of oxygen gas will o

ddd [48]

Answer : The mass of $O_2$ occupy 30.3 L under the same conditions will be, 24.9 grams.

Explanation :

First we have to calculate the moles of $O_2$

$\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}=\frac{5.12g}{32g/mol}=0.16mol$

Now we have to calculate the moles of $O_2$ in 30.3 L by using Avogadro's law.

Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

$V\propto n$

or,

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

where,

$V_1$ = initial volume of gas = 6.21 L

$V_2$ = final volume of gas = 30.3 L

$n_1$ = initial moles of gas = 0.16 mol

$n_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{6.21L}{0.16mol}=\frac{30.3L}{n_2}$

$n_2=0.781mol$

Now we have to calculate the mass of $O_2$

$\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2$

Molar mass of $O_2$ = 32 g/mol

$\text{ Mass of }O_2=(0.781moles)\times (32g/mole)=24.9g$

Therefore, the mass of $O_2$ occupy 30.3 L under the same conditions will be, 24.9 grams.

6 0

3 years ago