Plz answer I don't get this!!!

What happens when the preassure of gas is decreased?

NARA [144]

If you decrease the pressure of a fixed amount of gas, its volume will increase.

8 0

3 years ago

Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to o

Viefleur [7K]

Answer:

$P_2=404 kPa$

Explanation:

Hello,

In this case, the Boyle's is mathematically defined via:

$P_1V_1=P_2V_2$

Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:

$V_2=\frac{1}{4} V_1$

We can compute the new pressure:

$P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa$

Which means the pressure is increased by a factor of four.

Regards.

7 0

3 years ago

If 125 mg of Ar(g) is added to a 505-mL sample of Ar(g) at STP, what volume will the sample occupy when the conditions of STP ar

miss Akunina [59]

Answer:

The new volume will be 575 mL

Explanation:

Step 1: Data given

Mass of Ar = 125 mg = 0.125 grams

Volume = 505 mL = 0.505 L

Molar mass Ar = 39.95 g/mol

Step 2 : Calculate moles of Ar to start

n = PV/RT

⇒ with n = initial number of moles Ar

⇒ with p = pressure = 1.0 atm

⇒ with R = the gas constant = 0.08206 L* atm/mol *K

⇒ with V = the volume = 0.505 L

⇒ with T = the temperature = 273.15 K

n = 0.505 L * 1 atm / (0.08206 * 273.15 deg K) =0.02253 moles

Step 3: Calculate add moles of Ar

Moles Ar = mass Ar / molar mass Ar

Moles Ar = 0.125 g / 39.95 g/mol = 0.00313 moles

Step 4: Calculate total moles Ar

Total moles Ar = 0.02253 + 0.00313 = 0.02566 moles

Step 5: Calculate new volume

V = nRT/P

V = 0.02566 * 0.08206 * 273.15 / 1 atm

V = 0.575 L = 575 mL

The new volume will be 575 mL

4 0

3 years ago

How are alpha, beta and gamma radiation characterized in terms of mass and charge?

Anarel [89]

Beta radiation - negative charge and the mass of an electron
Gamma radiation- no mass and no charge
Alpha radiation- He 4+/2

7 0

3 years ago

Select the pair that consists of a base and its conjugate acid in that order. CO32−/CO22−

lana [24]

Answer: The pair that consists of a base and its conjugate acid in that order. $NH_3/NH_4^+$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

$H_3PO_4\rightarrow H_PO_4{2^-}+2H^+$

$H_2CO_3\rightarrow HCO_3^-+H^+$

$NH_3+H^+\rightarrow NH_4^+$

$HCO_3^-\rightarrow CO_3^{2-}+H^+$

$NH_3$ is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms $NH_4^+$ which is a conjugate acid.

3 0

3 years ago