The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Rational,whole,integer,real
Answer:
See step by step
Step-by-step explanation:
For A. use any two factors that multiply to 100 that isn't 25 and 4.
For b Use one obtuse angle (angle over 90 degree) and two acute angles. Make sure they add up to 180.
For c Use any two values that add up to 52 since they didnt establish y as the midpoint.
For d. measure of angle 1 is 45 and measure of angle 2 is 45 degrees
<h2>
Answer: <em><u>
Less Than</u></em></h2>
Step-by-step explanation: 7^2 = 49, but 3^4 = 81. 49 < 81
Answer:
Acute
Step-by-step explanation:
Note the definitions:
Obtuse: At least one of the angles are greater than 90°
Equilateral: All angles are congruent & equal to 60°
Acute: All angles are less than 90°
Right: At least one angle is equal to 90°
In this case, the triangle is a D) acute, for it fits the requirement for being an acute... all angles are less than 90°.
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