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Irina18 [472]
3 years ago
7

Are diamonds flammable?

Chemistry
2 answers:
Katen [24]3 years ago
6 0
Diamonds are not flammable, but are combustible, when a diamond burns there is no ash because diamonds are pure carbon and when burned it is turned into carbon dioxide.
:D
Debora [2.8K]3 years ago
4 0
A match-head is flammable, but you have to get it up to its ignition temperature first.

A diamond is flammable, but its ignition temperature is astronomical and
totally out of sight.
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CaC2 + 2H2O ⟶ C2H2 + Ca(OH)2<br><br> How many moles of water are needed to produce 56.8g C2H2?
pshichka [43]

Amount of moles of water is 4.36 mol

Explanation: M(C2H2) = 2·12.01 + 2·1.008 = 26.036 g/mol

Amount of substance is n= m/M= 56.8 g / 26.036 g/mol= 2.18159 mol

Water is needed 2·2.18 mol = 4.36 mol

6 0
3 years ago
Determine the number of grams of carbon 3.14x 1023 atoms of carbon
tiny-mole [99]
<h3>Answer:</h3>

6.26 g C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.14 × 10²³ atoms C

[Solve] grams C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 3.14 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})(\frac{12.01 \ g \ C}{1 \ mol \ C})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 6.26227 \ g \ C

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.26227 g C ≈ 6.26 g C

7 0
2 years ago
Read 2 more answers
Based on the activity series provided, which reactants will form products? f &gt; cl &gt; br &gt; i cui2 br2 right arrow. cl2 al
dimaraw [331]

The reactants that will form products will be 2CuI_2 + Br2.

<h3>Activity series</h3>

Elements at higher positions in the activity series will be able to displace those in lower positions in solutions.

Thus:

2CuI_2 + Br2 --- > 2CuBr +2 I_2 because Br is higher than I in the activity series.

Cl cannot displace F in Cl2 + AlF_3 because F is higher than Cl in the activity series.

Also, Cl is higher than Br in the activity series, thus, the reaction Br_2 + NaCl cannot form products.

I cannot displace F, thus, CuF_2 + I_2 cannot form products.

More on activity series can be found here: brainly.com/question/13934381

#SPJ1

5 0
2 years ago
for the reaction shown compute the theoretical yield of product in moles each of the initial quantities of reactants. 2 Mn(s)+3
Y_Kistochka [10]

Answer:

2 mole MnO₂

Explanation:

2Mn(s) + 2O₂(g) => 2MnO₂(s)

4 0
3 years ago
Read 2 more answers
Which of the following states that an orbital can contain two electrons only if all other orbitals at that sublevel contain at l
Vesnalui [34]
Isn't that Hund's rule????

5 0
3 years ago
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