Answer:
CH4(g) + 2O2(g) -------> CO2(g) + 2H2O(g)
Explanation:
Even though the question is incomplete because the equations are missing. However, one thing that is clear from the question is that the reaction is a combustion reaction.
A combustion reaction is a type of reaction that produces heat and light. The mixture of methane and oxygen yielded a brief, large flame which shows that combustion has taken place according to the equation shown above.
From this trend, Cesium is said to have the lowest ionization energy and Fluorine is said to have the highest ionization energy (with the exception of Helium and Neon). Fr (francium) has the lowest ionization energy. its radius is large and there is only in one electron in last energy level. therefore less amount of energy is needed to remove that electron.
When particles are heated they expand
Answer:
1.98 M
Explanation:
Given data
- Initial volume (V₁): 93.2 mL
- Initial concentration (C₁): 2.03 M
- Volume of water added: 3.92 L
Step 1: Convert V₁ to liters
We will use the relationship 1 L = 1000 mL.
![93.2mL \times \frac{1L}{1000mL} = 0.0932 L](https://tex.z-dn.net/?f=93.2mL%20%5Ctimes%20%5Cfrac%7B1L%7D%7B1000mL%7D%20%3D%200.0932%20L)
Step 2: Calculate the final volume (V₂)
The final volume is the sum of the initial volume and the volume of water.
![V_2 = 0.0932L + 3.92 L = 4.01L](https://tex.z-dn.net/?f=V_2%20%3D%200.0932L%20%2B%203.92%20L%20%3D%204.01L)
Step 3: Calculate the final concentration (C₂)
We will use the dilution rule.
![C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M](https://tex.z-dn.net/?f=C_1%20%5Ctimes%20V_1%20%3D%20C_2%20%5Ctimes%20V_2%5C%5CC_2%20%3D%20%5Cfrac%7BC_1%20%5Ctimes%20V_1%7D%7BV_2%7D%20%3D%20%5Cfrac%7B2.03%20M%20%5Ctimes%203.92L%7D%7B4.01L%7D%20%3D%201.98%20M)