The arrow that are drawn correctly are the cool air current and the upper air current. In the sea breeze, warm air moves up because it is less dense that the cool air. The cool air moves down to replace the warm air. The land breeze current moves from the land to the sea while the sea breeze moves from the sea to the land. This creates a continuous flow of current at the sea level.
Answer:
ΔS > 0 only for choice E: CH4(g) + H2O (g) → CO(g) + 3 H2(g)
Explanation:
Our strategy in this question is to use the trend in entropies :
S (solids) less than S (liquids) less than S (gases)
Also we have to look for the molar quanties involved of each state and their change to answer the question:
A. N2(g) + 3 H2(g) → 2 NH3(g)
Here we have 4 moles gases going to 2 moles of products, so the change in entropy is negative.
B. Na2CO3(s) + H2O(g) + CO2(g) → 2 NaHCO3(s)
The change in entropy is negative since we have 2 mol gases in the reactants and zero in the products.
C. CH3OH(l) → CH3OH(s)
A liquid has a higher entropy than a solid so ΔS is negative
D. False see A,B,C
E. The change in moles of gases is 4 - 2= 2, therefore ΔS is greater than O.
Answer:
dihydrogen dioxide, hydrogen dioxide, hydrogen oxide, oxydol, peroxide, H 2 O 2.