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Alina [70]
3 years ago
5

Why is the fuse used in a circuit called safety fuse?​

Physics
2 answers:
Mazyrski [523]3 years ago
6 0

Answer:

The guy above me is right

Explanation:

Sunny_sXe [5.5K]3 years ago
4 0

Answer:

The maximum current which can flow through a fuse without melting it, is called its rating. ... If current higher than 8 A flows through the fuse, it would melt and circuit gets broken. ... Hence, fuse acts as a safety device

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timama [110]

Answer:

no, otherwise they just cause a side effect on our lives

8 0
3 years ago
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A light bulb in a camper’s flashlight is labeled 4.1 V, 0.40 A. Find the equivalent current if three of these light bulbs are co
Gnesinka [82]

Explanation:

first rule of parallel circuits : the voltage is the same in the whole circuit, no matter where we measure.

so, we have 1.5V at every bulb.

second rule of parallel circuits : the total current is the sum of the individual branch currents.

so, if the battery really allows it, then we have 3 times 0.4 A = 3×0.4 = 1.2 A as current in the circuit.

5 0
2 years ago
A charge q of 1.3 × 10-16 coulombs moves from point A to a lower potential at point B in an electric field of 3.2 × 102 newtons/
LUCKY_DIMON [66]

Explanation :

It is given that,

Charge, q=1.3\times 10^{-16}\ C

Electric field, E=3.2\times 10^2\ N/C

Distance, d=1.1\times 10^{-2}\ m

The work done is stored in the form of potential energy.

W=F.d

\because F=qE

So, W=qE\ d

W=1.3\times 10^{-16}\ C\times 3.2\times 10^2\ N/C\times 1.1\times 10^{-2}\ m

W=4.576\times 10^{-16}\ J

Hence, this is the required solution.

5 0
3 years ago
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my choice1A child pushes a toy truck up an inclined plane. The lifting force is...Select one:ut ofO a. the weight of the truck.O
mash [69]

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Therefore the correct option is C.

4 0
1 year ago
A LASIK vision-correction system uses a laser that emits 10-ns-long pulses of light, each with 3.0 mJ of energy. The laser beam
lyudmila [28]
 <span>P = energy/t = 0.0025/1E-8 = 250000 W 
I(ave) = P/A = 250000/(pi*0.425E-3^2) = 4.4056732E11 W/m^2 
I(peak) = 2I(ave) = 8.8113463E11 W/m^2 
Electric field E = sqrt(I(peak)*Z0) = 1.8219499E7 V/m, where 
free-space impedance Z0 = sqrt(µ0/e0) = 376.73031 ohms</span>
7 0
3 years ago
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