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Scorpion4ik [409]
4 years ago
10

True or false An object that is not accelerating or decelerating has zero net force acting in it.

Physics
1 answer:
Rashid [163]4 years ago
6 0
False, gravity is always acting on any object
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An electromagnetic wave in vacuum has an electric field amplitude of 470 V/m. Calculate the amplitude of the corresponding magne
lapo4ka [179]

Answer:

Magnetic field, B = B=1.56\times 10^{-6}\ T

Explanation:

It is given that,

The amplitude of an electromagnetic wave, E = 470 V/m

We need to find the amplitude of the corresponding magnetic field. The relation between electric and magnetic field is :

B=\dfrac{E}{c}

Where

c is the speed of light

B=\dfrac{470\ V/m}{3\times 10^8\ m/s}

B = 0.00000156

B=1.56\times 10^{-6}\ T

So, the amplitude of the corresponding magnetic field is 1.56\times 10^{-6}\ T. Hence, this is the required solution.

6 0
4 years ago
The state in which the inside of each heart cell is negatively charged and the outside is positively charged is:
densk [106]

Answer:

Resting state

Explanation:

5 0
3 years ago
A tuba creates a 4th harmonic of
xxTIMURxx [149]

Answer:

93.54 Hz

Explanation:

✓From the question, Number of harmonic frequency is 4

✓ the frequency (f₄ )= 116.5 Hz

✓harmonic frequency can be calculated using below expresion

fₙ = [ (nv)/4L]..........eqn(1)

v = speed of sound= 343 m/s

n = number of given harmonic frequency

L = Length of the rope

Using above expresion ,and substitute the values at (n=4) which is 4th harmonic frequency to find the " initial Lenght of the rope

fₙ = [ (nv)/4L]

f₄ = 4× 343 /4L

f₄ = 343 /L

L= 343 /f₄

But f₄= 116.5 Hz

L= 343/116.5= 2.944m

Hence, initial Lenght of the rope= 2.944m

We can determine the frequency of new length as ( initial Lenght of the rope + tubing Lenght)

= ( 2.944m + 0.721m )

= 3.667m

Hence, new length= 3.667m

To find the new frequency of the 4th harmonic we will use eqn(2)

f₄ = v/l ...............eqn(2)

From equation (2) If we substitute the values we have

f₄ = (343/3.667)

= 93.54 Hz

Hence, the the new frequency of the 4th harmonic is

93.54 Hz

4 0
3 years ago
An object of mass m has these three forces acting on it (there is no normal force, "no surface"). F1 = 5 N, F2 = 8 N, and F3 = 5
DIA [1.3K]

The figure is missing: find it in attachment.

a) (3i - 5j) N

First of all, we have to write each force as a vector with a direction:

- Force F1 points downward, so along the negative y-direction, so we can write it as

F_1 = -5 j

- Force F2 points to the right, so along the positive x-direction, so we can write it as

F_2 = +8 i

- Force F3 points to the left, so along the negative x-direction, so we can write it as

F_3 = -5 i

Now we can write the net force, by adding the three vectors and separating the x-component from the y-component:

F=F_1+F_2+F_3 = -5j+8i-5i = (8-5)i+(-5)j=(3i-5j)N

b) 5.8 N

The magnitude of the net force can be calculated by applying Pythagorean's theorem on the components of the net force:

F=\sqrt{F_x^2+F_y^2}

where

F_x = 3 N is the x-component

F_y = -5 N is the y-component

Substituting into the equation,

F=\sqrt{(3)^2+(-5)^2}=5.8 N

c) -59.0^{\circ}

The angle of the net force, measured with respect to the positive x-axis (counterclockwise), can be calculated by using the formula

\theta=tan^{-1} (\frac{F_y}{F_x})

where

F_x = 3 N is the x-component

F_y = -5 N is the y-component

Substituting into the equation, we find

\theta = tan^{-1} (\frac{-5}{3})=-59.0^{\circ}

d) 0.84 m/s^2

The acceleration can be found by using Newton's second law:

F=ma

where

F is the net force on an object

m is its mass

a is the acceleration

For the object in the problem, we know

F = 5.8 N

m = 6.9 kg

Solving the equation for a, we find the magnitude of the acceleration:

a=\frac{F}{m}=\frac{5.8}{6.9}=0.84 m/s^2

4 0
3 years ago
Given a force of 88n and an acceleration of 4m/s2 what is the mass?
Hitman42 [59]
F=ma
m=F/a = 88/4 = 22 kg

5 0
3 years ago
Read 2 more answers
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