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3 years ago

I need to learn how to solve 2v^2+8=50

Mathematics

1 answer:

sukhopar [10]3 years ago

4 0

Answer:

In order to solve this, you would subtract 8 from both sides. 8 minus 8 cancels out and 50 minus 8 minus 42.

Now, the equation should read like 2v^2=42. You would then divide both sides by 2v^2. 2v^2 divided by itself by cancels out which would leave you with 42/2v^2.

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Find the value of k so that the graph of 13y + kx = 4 and the line containing the points (5, -8) and (2, 4) are parallel.

guajiro [1.7K]

the graph of 13y + kx = 4 and the line containing the points (5, -8) and (2, 4) are parallel.

We find the slope of parallel line using two given points

(5, -8) and (2, 4)

Slope formula is

$slope = \frac{y_2-y_1}{x_2-x_1}$

$slope = \frac{4-(-8)}{2-5}$

$slope = \frac{12)}{-3}=-4$

so slope = -4

Slope of any two parallel lines are always equal

Lets find the slope of the equation 13y + kx = 4

Subtract kx on both sides

13 y = -kx + 4

Divide both sides by 13

$y= \frac{-kx}{13} + \frac{4}{13}$

Now slope = -k/13

We know slope of parallel lines are same

So the slope of 13y + kx = 4 is also -4

Hence we equation the slope and find out k

$\frac{-k}{13}=-4$

Multiply by 13 on both sides and divide by -1

k = 52

the value of k = 52

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