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Maksim231197 [3]
4 years ago
7

Radioactive isotope #1 has been kept for 1.5 years. Originally, there were 100 grams and now there are 99.39 grams. When will th

ere be 1 gram left?
Mathematics
1 answer:
Nina [5.8K]4 years ago
5 0
First we calculate the half-life
half-life = elapsed time * log(2) / log (beginning amt / ending amt)
half-life = 1.5 * <span> <span> <span> 0.3010299957 </span> </span> </span> / log( <span> <span> <span> 1.0061374384 </span> </span> </span> )
half-life = <span> <span> </span></span><span>1.5 * <span> <span> 0.3010299957 </span> </span> / 0.0026573094 </span>
<span><span><span>half-life = </span> </span> </span> 169.93 years

Now we have to calculate elapsed time for 100 grams to become 1
elapsed time = half-life * log (bgng amt / end amt) / log (2)
elapsed time = 169.93 * log (100/1) / log(2)
elapsed time = 169.93 * 2 / <span> <span> <span> 0.3010299957 </span> </span> </span>
elapsed time = 1,129 years

Source:
http://www.1728.org/halflife.htm







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Is x + 10 a factor of the function f(x) = x3 − 75x + 250? Explain.
PtichkaEL [24]
Yes. When the function f(x) = x3 – 75x + 250 is divided by x + 10, the remainder is zero. Therefore, x + 10 is a factor of f(x) = x3 – 75x + 250. 

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