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jeka57 [31]
3 years ago
5

Find the sum of this infinite geometric series. HELP!!

Mathematics
2 answers:
Vaselesa [24]3 years ago
4 0
The sum of the geometric series is 128
xxTIMURxx [149]3 years ago
3 0
The answer would be 128!!!
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Pleasehelp me algebra 2
leva [86]
The average rate of change is 12.

27 - 3 = 24.

1 - (-1) = 2 [it’s essentially 1 + 1].

24/2 = 12.
4 0
3 years ago
the larger of two positive numbers is 5 more then the smaller. The product of the numbers is 66. find the numbers
Serjik [45]

Answer: 30.5 and 35.5

Step-by-step explanation:

We can use a system of linear equations to find out the answer to this problem. The larger number will be x and the smaller number will be y.

x=y+5

x+y=66

Substitute y+5 in for the bottom equation to get y+5+y=66. Simplify to get 2y+5=66. Subtract 5 from both sides and get 2y=61. Divide by 2 to get y=30.5. This is the smaller number. Add 5 to get the bigger number, which is 35.5

7 0
3 years ago
Please, can someone help?
LekaFEV [45]
The area of that figure is 2453.25 square feet

First, you would need to find the area of the rectangle

(L)(W)
(70)(30)
2100

Then since it is only a semi circle, the formula is pi*r^2/2

You find the area of a full circle first

(3.14)(15^2)
(3.14)(225)
706.5

Then you divide that by 2 since it’s only half a circle

706.5/2 = 353.25

Finally you add that by the area of the rectangle

2100 + 353.25 = 2453.25 square feet
3 0
3 years ago
Identify the expressions for which limits exist.
alexdok [17]

Answer:

..............

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Can someone explain how to do "interquartile range"
Andrews [41]

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

<em>Step 1: Put the numbers in order. ...</em>

<em>Step 2: Find the median. ...</em>

<em>Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...</em>

<em>Step 4: Find Q1 and Q3. ...</em>

<em>Step 5: Subtract Q1 from Q3 to find the interquartile range.</em>

7 0
2 years ago
Read 2 more answers
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