X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9
We can find the area of the big triangle, and subtract it from the small 4 x 2 triangle.
bh/2
3*8/2
12
bh/2
2*4/4
4
12 - 8
4 unit²
To find the perimeter:
a² + b² = c²
9 + 64 = c²
73 = c²
√73 = c
√73 + 3 + 8 + 2 + 4
√73 + 17
Hope this helps!
Answer:
1,870
Step-by-step explanation:
