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Mariulka [41]
4 years ago
5

Please help. Winter break packets are the worst :/

Mathematics
2 answers:
Sophie [7]4 years ago
6 0
Y = kx or k = y/x or x = y/k

5) y = kx = (1.5)(50) = 75
6) x = y/k = (15/4) / (1/4) = 15/4 x 4 = 15
7) y = kx = (1/2)(14/5) = 7/5 or = 1 2/5 or = 1.4
8) x = y/k = 38/16 = 2.375


erik [133]4 years ago
3 0
Y/50=1.5
y=75

3.75/x=.25
3.75/.25=x
x=15

y/2.8=.5
y=1 2/5

38/x=16
38/16=x
19/8=x
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Please answer the 3rd Question please answer it fast............I WILL MARK YOU AS THE BRANLIEST.................
mojhsa [17]

since LM=LN there values are same which is given as 5.5 cm and MN =7cm

now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs  will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!

Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.

<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>

8 0
3 years ago
Find the surface area of the composite solid.
Illusion [34]

The ends of the rectangle = 10*10*2 = 200

The long sides and bottom of the rectangle = 12*10*3 = 360

Vertical end of the triangle = 5*10 = 50

The sides of the triangle = 12*5*1/2*2 = 60

Triangle slope = 13*10 = 130

Total = 200 + 360 + 50 + 60 + 130 =

800 in sq

7 0
3 years ago
Read 2 more answers
Help plz!!!!!!!!!!!!!!!!!!!!!!!!
melisa1 [442]
I got the last answer.

Y = 2x - 2


4 0
3 years ago
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Find the area of the triangle below.
DaniilM [7]

Answer: 24

Step-by-step explanation:

8 0
3 years ago
Can someone pleaseeee help and if you’re correct i’ll give brainliest
Lynna [10]

Answer:

Hexagon

Step-by-step explanation:

It has more than 3 sides because it is more sides than a triangle and less than 5 since it has to be fewer sides than a pentagon. A hexagon has 6 sides meaning it has more sides than the pentagon.

4 0
3 years ago
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